document.write( "Question 1208605: If 1/8 + 1/3 = 1/N, what is the value of N?\r
\n" ); document.write( "\n" ); document.write( "I have worked on this problem and so far I have gotten to the point where 1/8 +1/3 =11/24 and I am stuck on where to go from here. I also need to write a formal solution for this so any insight regarding how to write a formal solution would also be greatly appreciated.
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Algebra.Com's Answer #846971 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "There are at least two methods to solve this.\r
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\n" ); document.write( "\n" ); document.write( "Method 1
\n" ); document.write( "1/8 + 1/3 = 1/N
\n" ); document.write( "3/24 + 8/24 = 1/N
\n" ); document.write( "(3+8)/24 = 1/N
\n" ); document.write( "11/24 = 1/N ........... this is what you have so far
\n" ); document.write( "11N = 24 ........... cross multiply
\n" ); document.write( "N = 24/11\r
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\n" ); document.write( "\n" ); document.write( "Method 2
\n" ); document.write( "1/8 + 1/3 = 1/N
\n" ); document.write( "24N*(1/8 + 1/3) = 24N(1/N) ........... multiply both sides by LCD to clear out fractions
\n" ); document.write( "24N*(1/8) + 24N*(1/3) = 24N(1/N)
\n" ); document.write( "3N + 8N = 24
\n" ); document.write( "11N = 24
\n" ); document.write( "N = 24/11\r
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\n" ); document.write( "\n" ); document.write( "Side note:
\n" ); document.write( "24/11 = 2.181818...
\n" ); document.write( "the \"18\" repeats forever.
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