document.write( "Question 1208601: Mail Order A mail order company has a 6% success rate. If it mails advertisements to 525 people, find the probability of getting less than 27 sales. Use The Standard Normal Distribution Table. Round z-value calculations to 2 decimal places and final answer to at least 4 decimal places.\r
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document.write( "P(X<27)= \n" );
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Algebra.Com's Answer #846961 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: 0.17879\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Explanation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We have a binomial distribution with these parameters \n" ); document.write( "n = 525 = sample size \n" ); document.write( "p = 0.06 = probability of success\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To ensure we can use a normal distribution to approximate this binomial distribution, we must check that n*p > 5 and n*(1-p) > 5 \n" ); document.write( "n*p = 525*0.06 = 31.5 \n" ); document.write( "n*(1-p) = 525*(1-0.06) = 493.5 \n" ); document.write( "Both results exceed 5, so the requirements are met. \n" ); document.write( "Some textbooks will raise the threshold to n*p > 10 and n*(1-p) > 10. The results also meet these requirements.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "mu = n*p = 525*0.06 = 31.5 is the mean \n" ); document.write( "sigma = sqrt(n*p*(1-p)) = sqrt(525*0.06*(1-0.06)) = 5.44150714 is the approximate standard deviation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Using a continuity correction factor, we'll adjust P(X < 27) to get P(X < 26.5)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Compute the z score. \n" ); document.write( "z = (x - mu)/sigma \n" ); document.write( "z = (26.5 - 31.5)/5.44150714 \n" ); document.write( "z = -0.91886307807 \n" ); document.write( "z = -0.92 is the approximate z score when rounding to 2 decimal places.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then use the Standard Normal Distribution Table (also known as Z table) that your teacher has provided you. \n" ); document.write( "Usually such a table is found in the back of your stats textbook.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Locate the row that starts with -0.9 \n" ); document.write( "Highlight the column that has 0.02 at the top. \n" ); document.write( "The value 0.17879 is in this row and column. \n" ); document.write( "This value is approximate. \n" ); document.write( "We can say that P(Z < -0.92) = 0.17879 which is the approximate final answer in decimal form. \n" ); document.write( " \n" ); document.write( " |