document.write( "Question 116496: log 2(4)= 4x+1 \n" ); document.write( "

Algebra.Com's Answer #84696 by stanbon(75887) $\"\"$ $\"About$

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log 2(4)= 4x+1
\n" ); document.write( "-------------------
\n" ); document.write( "2^(4x+1) = 4
\n" ); document.write( "2^(4x+1) = 2^2
\n" ); document.write( "4x+1 = 2
\n" ); document.write( "4x = 1
\n" ); document.write( "x = 1/4
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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