document.write( "Question 116382:
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document.write( "The length of a rectangle is 7 less than 3 times the width. If the perimeter is 34, find the dimensions. \n" );
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Algebra.Com's Answer #84675 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! PERIMETER=2L+2W \n" ); document.write( "L=3W-7 \n" ); document.write( "2(3W-7)+2W=34 \n" ); document.write( "6W-14+2W=34 \n" ); document.write( "8W=34+14 \n" ); document.write( "8W=48 \n" ); document.write( "W=48/8 \n" ); document.write( "W=6 ANSWER FOR THE WIDTH. \n" ); document.write( "L=3*6-7 \n" ); document.write( "L=18-7 \n" ); document.write( "L=11 ANSWER FOR THE LENGTH. \n" ); document.write( "PROOF \n" ); document.write( "2*11+2*6=34 \n" ); document.write( "22+12=34 \n" ); document.write( "34=34 \n" ); document.write( " \n" ); document.write( " |