document.write( "Question 116382:
\n" ); document.write( "The length of a rectangle is 7 less than 3 times the width. If the perimeter is 34, find the dimensions.
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Algebra.Com's Answer #84675 by checkley71(8403)\"\" \"About 
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PERIMETER=2L+2W
\n" ); document.write( "L=3W-7
\n" ); document.write( "2(3W-7)+2W=34
\n" ); document.write( "6W-14+2W=34
\n" ); document.write( "8W=34+14
\n" ); document.write( "8W=48
\n" ); document.write( "W=48/8
\n" ); document.write( "W=6 ANSWER FOR THE WIDTH.
\n" ); document.write( "L=3*6-7
\n" ); document.write( "L=18-7
\n" ); document.write( "L=11 ANSWER FOR THE LENGTH.
\n" ); document.write( "PROOF
\n" ); document.write( "2*11+2*6=34
\n" ); document.write( "22+12=34
\n" ); document.write( "34=34
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