document.write( "Question 1208352: Going into the final exam, which will count as 2/3 of the final grade, Larry has test scores of 86, 80, 84, and 90. What score does Larry need on the final exam in order to earn a B, which requires an average score of 80? What does he need to earn an A, which requires an average score of 90?\r
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\n" ); document.write( "\n" ); document.write( "To Earn a B:\r
\n" ); document.write( "\n" ); document.write( "(86 + 80 + 84 + 90 + B)/5 = 80\r
\n" ); document.write( "\n" ); document.write( "To Earn an A:\r
\n" ); document.write( "\n" ); document.write( "(86 + 80 + 84 + 90 + A)/5 = 90\r
\n" ); document.write( "\n" ); document.write( "What do you say about my setup?
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Algebra.Com's Answer #846729 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "Your equations would only be right if the final exam counted only as much as each test. You need to weight the score on the final appropriately.

\n" ); document.write( "There are 4 test scores which count for 1/3 of the grade, and the final counts or 2/3 of the grade. Since the final counts twice as much as the 4 tests, the final has a weight equivalent to 8 tests (making 12 \"tests\").

\n" ); document.write( "So to answer the two questions by the method you are using, you could use the equations

\n" ); document.write( "(86+80+84+90+8A)/12 = 90

\n" ); document.write( "and

\n" ); document.write( "(86+80+84+90+8B)/12 = 80

\n" ); document.write( "That first equation will give you the same answer as shown by the other tutor using a different method. As he did, I leave it to you to solve the second problem to find the score needed to get a B.

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