document.write( "Question 1208352: Going into the final exam, which will count as 2/3 of the final grade, Larry has test scores of 86, 80, 84, and 90. What score does Larry need on the final exam in order to earn a B, which requires an average score of 80? What does he need to earn an A, which requires an average score of 90?\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "To Earn a B:\r
\n" );
document.write( "\n" );
document.write( "(86 + 80 + 84 + 90 + B)/5 = 80\r
\n" );
document.write( "\n" );
document.write( "To Earn an A:\r
\n" );
document.write( "\n" );
document.write( "(86 + 80 + 84 + 90 + A)/5 = 90\r
\n" );
document.write( "\n" );
document.write( "What do you say about my setup? \n" );
document.write( "
Algebra.Com's Answer #846729 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Your equations would only be right if the final exam counted only as much as each test. You need to weight the score on the final appropriately. \n" ); document.write( "There are 4 test scores which count for 1/3 of the grade, and the final counts or 2/3 of the grade. Since the final counts twice as much as the 4 tests, the final has a weight equivalent to 8 tests (making 12 \"tests\"). \n" ); document.write( "So to answer the two questions by the method you are using, you could use the equations \n" ); document.write( "(86+80+84+90+8A)/12 = 90 \n" ); document.write( "and \n" ); document.write( "(86+80+84+90+8B)/12 = 80 \n" ); document.write( "That first equation will give you the same answer as shown by the other tutor using a different method. As he did, I leave it to you to solve the second problem to find the score needed to get a B. \n" ); document.write( " \n" ); document.write( " |