document.write( "Question 1208311: How many intergers between 31 and 131 are divisible by 7 but not divisible by 6? \n" ); document.write( "
Algebra.Com's Answer #846650 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! 31/7 = 4.4286 \n" ); document.write( "7*4 = 28 is too small but 7*5 = 35 fits \n" ); document.write( "131/7 = 18.7143 \n" ); document.write( "7*18 = 126 also fits \n" ); document.write( "7*19 = 133 is too large.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The multiples of 7 between 31 and 131 are: {35, 42, 49, ..., 126} \n" ); document.write( "They can be written as {7*5, 7*6, 7*7, ..., 7*12, ..., 7*18}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Cross off 7*6, 7*12 and 7*18 since they involve 6 as a factor. \n" ); document.write( "There are 14 items in the set {5,6,7,...,18} because 18-5+1 = 14. Or you can count out the items. \n" ); document.write( "That must mean there are also 14 items in the set {7*5,7*6,...,7*18} = {35,42,...,126} \n" ); document.write( "We crossed off 3 items {7*6,7*12,7*18} so we have 14-3 = 11 multiples of 7 between 31 and 131 such that 6 isn't a factor. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 11 \n" ); document.write( " |