document.write( "Question 1208302: z = [1, theta ] , find (z + z ^(10))/(z - z ^(10)) by Polar form [ r , theta ], \n" ); document.write( "
Algebra.Com's Answer #846636 by ikleyn(52794)\"\" \"About 
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\n" ); document.write( "z = (1,theta), find (z + z^(10))/(z - z^(10)) \"highlight%28cross%28by%29%29\" in polar form (r,theta).
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document.write( "In cis-form,  z = \"cis%281%2Ctheta%29\".   It means that the modulus of z is 1 and the argument of z is \"theta\".\r\n" );
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document.write( "Then  \"z%5E10\" = \"cis%281%2C10%2Atheta%29\".  In other words,  \"z%5E10\" has the modulus 1  and the argument of  \"10%2Atheta\".\r\n" );
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document.write( "To find the sum  z + \"z%5E10\",  you should use the parallelogram rule of adding complex numbers as vectors.\r\n" );
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document.write( "Since both addends,  z  and  \"z%5E10\"  have equal modulus, the parallelogram rule in this case becomes\r\n" );
document.write( "the rhombus rule.  In rhombus, the diagonal is the bisector of the angle.  \r\n" );
document.write( "THEREFORE, in our case the argument of  \"z%2Bz%5E10\"  is\r\n" );
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document.write( "    \"%28theta%2B10%2Atheta%29%2F2%29\" = \"5.5%2Atheta%29\". \r\n" );
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document.write( "The modulus of  \"z%2Bz%5E10\"  is the third side of an isosceles triangle with the equal legs of the length 1 \r\n" );
document.write( "and the angle between these legs of  \"10%2Atheta+-+theta\" = \"9%2Atheta\"\r\n" );
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document.write( "    A = \"sqrt%281%5E2+%2B+1%5E2+-+2%2Acos%289%2Atheta%29%29\" = \"sqrt%282-2cos%289%2Atheta%29%29\".\r\n" );
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document.write( "So,  \"z+%2B+z%5E10\" = \"cis%28A%2C5.5%2Atheta%29\".\r\n" );
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document.write( "Similarly, for the denominator\r\n" );
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document.write( "    \"z+-+z%5E10\" = \"cis%28B%2C%28theta-10%2Atheta%29%2F2%29\" = \"cis%28B%2C-4.5%2Atheta%29%29\",\r\n" );
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document.write( "where  B = \"sqrt%282%2B2%2Acos%289%2Atheta%29%29\".   <<<---=== Note that the angle between  z  and  \"-z%5E10\"  is  \r\n" );
document.write( "                                             \"%2810%2Atheta%2Bpi%29-theta\" = \"9%2Atheta%2Bpi\"\r\n" );
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document.write( "                                             and  \"cos%289%2Atheta%2Bpi%29\" = \"-cos%289%2Atheta%29\".\r\n" );
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document.write( "Thus the ratio  \"%28z+%2B+z%5E%2810%29%29%2F%28z+-+z%5E%2810%29%29\"  has the modulus  \r\n" );
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document.write( "    \"sqrt%282-2cos%289%2Atheta%29%29%2Fsqrt%282%2B2cos%289%2Atheta%29%29\" = \"sqrt%281-cos%289%2Atheta%29%29%2Fsqrt%281%2Bcos%289%2Atheta%29%29\"   \r\n" );
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document.write( "and the argument as the difference\r\n" );
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document.write( "    \"5.5%2Atheta+-+%28-4.5%2Atheta%29\" = \"%285.5%2B4.5%29%2Atheta\" = \"10%2Atheta\".\r\n" );
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document.write( "Using formulas   \"sqrt%281-cos%28a%29%29%2F2\" = \"sin%28a%2F2%29\",  \"sqrt%281%2Bcos%28a%29%29%2F2\" = \"cos%28a%2F2%29\",  the modulus of the ratio can be simplified\r\n" );
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document.write( "    \"sqrt%281-cos%289%2Atheta%29%29%2Fsqrt%281%2Bcos%289%2Atheta%29%29\"  = \"abs%28sin%28%289%2Atheta%29%2F2%29%2Fcos%28%289%2Atheta%29%2F2%29%29\" = \"abs%28sin%284.5%2Atheta%29%2Fcos%284.5%2Atheta%29%29\"\r\n" );
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document.write( "Therefore, the ratio  \"%28z+%2B+z%5E%2810%29%29%2F%28z+-+z%5E%2810%29%29\"  is  \"cis%28sqrt%281-cos%289%2Atheta%29%29%2Fsqrt%281%2Bcos%289%2Atheta%29%29%2C10%2Atheta%29\",  or, which is the same, (\"abs%28sin%284.5%2Atheta%29%2Fcos%284.5%2Atheta%29%29\",\"10%2Atheta%29\").\r\n" );
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document.write( "ANSWER.  In polar form,  \"%28z+%2B+z%5E%2810%29%29%2F%28z+-+z%5E%2810%29%29\"  is   (\"abs%28sin%284.5%2Atheta%29%2Fcos%284.5%2Atheta%29%29\",\"10%2Atheta%29\"). \r\n" );
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\n" ); document.write( "\n" ); document.write( "The key ideas of solution are \r
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\n" ); document.write( "\n" ); document.write( "     - use cis-form of complex numbers;\r
\n" ); document.write( "\n" ); document.write( "     - use the parallelogram rule to add and to subtract complex numbers;\r
\n" ); document.write( "\n" ); document.write( "     - use the fact that the parallelogram rule in the case of equal modulus becomes the rhombus rule;\r
\n" ); document.write( "\n" ); document.write( "     - use the fact that in rhombus a diagonal bisects the angle of the rhombus\r
\n" ); document.write( "\n" ); document.write( "     - to find the modulus of the numerator and denominator, use the cosine law.
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\n" ); document.write( "\n" ); document.write( "The rest is just arithmetic  (quite tight).\r
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\n" ); document.write( "\n" ); document.write( "This problem is special. Its level is much higher than the average high school Math;
\n" ); document.write( "it is higher than teachers teach in Math schools, higher than average Math circles level,
\n" ); document.write( "different from regular Math Olympiads.\r
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\n" ); document.write( "\n" ); document.write( "It is the level of Math Olympiads among undergraduate Math students of Math departments
\n" ); document.write( "of renowned universities/colleges, like the Putnam competition.\r
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\n" ); document.write( "\n" ); document.write( "It does not require \"flight of thought\", but requires solid and firm knowledge of complex numbers
\n" ); document.write( "in all relevant aspects and firm knowledge of relevant adjacent Math subjects,
\n" ); document.write( "together with perfect and firm Math technique.\r
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