document.write( "Question 1208278: Find dy/dx for x^3+2xy^2 = sin y \n" ); document.write( "
Algebra.Com's Answer #846602 by Edwin McCravy(20060)\"\" \"About 
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Find dy/dx for x^3+2xy^2 = sin y
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document.write( "An alternate method is to use partial derivatives of multivariable calculus. \r\n" );
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document.write( "For f(x,y)=0, we have the chain rule ∂f/∂x = -(∂f/∂y)(dy/dx) \r\n" );
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document.write( "\"dy%2Fdx\"\"%22%22=%22%22\" -(∂f/∂x)/(∂f/∂y)\r\n" );
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document.write( "Let \"%22f%28x%2Cy%29%22\"\"%22%22=%22%22\"\"x%5E3%2B2xy%5E2-sin%28y%29\"\"%22%22=%22%22\"\"0\"\r\n" );
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document.write( "then \"dy%2Fdx\"\"%22%22=%22%22\"\"-expr%28%283x%5E2%2B2y%5E2%29%2F%284xy-cos%28y%29%5E%22%22%29%29\"\r\n" );
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document.write( "\"dy%2Fdx\"\"%22%22=%22%22\"\"expr%28%283x%5E2%2B2y%5E2%29%2F%28cos%28y%29%5E%22%22-4xy%29%29\"\r\n" );
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document.write( "Edwin
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