document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1208239>Question 1208239</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A sugar ant is approximately 2 × 10^−3 meters long. If you put 10 million sugar<BR>\n" );
document.write( "ants in a line, what is the distance from end to end?<BR>\n" );
document.write( " 200 meters<BR>\n" );
document.write( " 2,000 meters<BR>\n" );
document.write( " 20,000 meters<BR>\n" );
document.write( " 200,000 meters </SPAN>\n" );
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document.write( "Answer: <font color=red>20,000 meters</font>\r<BR>\n" );
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document.write( "Work Shown\r<BR>\n" );
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document.write( "10 million = 10*(1 million) <BR>\n" );
document.write( "= 10*10^6 <BR>\n" );
document.write( "= 10^1*10^6 <BR>\n" );
document.write( "= 10^(1+6) <BR>\n" );
document.write( "= 10^7<BR>\n" );
document.write( "In short, 10 million = 10^7.<BR>\n" );
document.write( "Or put another way, 10 million = 10,000,000 = 1 followed by 7 zeros. The exponent tells us how many zeros are tacked onto the 1.\r<BR>\n" );
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document.write( "a = 2*10^(-3) = length of one ant in meters<BR>\n" );
document.write( "b = 10^7 = number of ants<BR>\n" );
document.write( "c = a*b = total length, in meters, of that number of ants assuming no gaps or overlaps. <BR>\n" );
document.write( "We also assume the ants form a straight line. \r<BR>\n" );
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document.write( "c = a*b<BR>\n" );
document.write( "c = 2*10^(-3)*10^7<BR>\n" );
document.write( "c = 2*10^(-3+7)<BR>\n" );
document.write( "c = 2*10^(4)<BR>\n" );
document.write( "c = 2*10,000<BR>\n" );
document.write( "c = <font color=red>20,000 meters</font>\r<BR>\n" );
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document.write( "Notes:<ul><li>I used the exponent rule a^b*a^c = a^(b+c).</li><li>20,000 meters = 20 kilometers</li><li>20 kilometers = 12.4274 miles approximately</li><li>20 kilometers = 6,5616.7979 feet approximately</li><li>2*10^(-3) meters = 0.002 meters = 2 mm</li></ul></font> </SPAN>\n" );
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