document.write( "Question 116439: Find all sets of three consecutive multiples of 6 whose sum is between -6 and 50.
\n" ); document.write( "I did it as -
\n" ); document.write( "-6 < 3x + 18 > 50
\n" ); document.write( "= -8 < x > 10.4
\n" ); document.write( "What is the correct answer?
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #84651 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
LET X, X+6 & X+12 BE THE 3 NUMBERS.
\n" ); document.write( "6<(3X+18)<50
\n" ); document.write( "CHECK FOR THE LOWER BOUNDRY
\n" ); document.write( "6<3X+18
\n" ); document.write( "6-18<3X
\n" ); document.write( "-12<3X
\n" ); document.write( "-12/3\n" ); document.write( "-4\n" ); document.write( "LET X=-3 & SEE IF IT IS A SOLUTION
\n" ); document.write( "-3+(-3+6)+(-3+12)<50
\n" ); document.write( "-3+3+9<50
\n" ); document.write( "9<50 SO -3,3&9 ARE ACCEPTABLE NUMBERS.
\n" ); document.write( "NOW WE TRY FOR THE UPPER LIMIT
\n" ); document.write( "X+(X+6)+(X+12)<50
\n" ); document.write( "3X+18<50
\n" ); document.write( "3X<50-18
\n" ); document.write( "3X<32
\n" ); document.write( "X<32/3
\n" ); document.write( "X<10.67
\n" ); document.write( "LET X=10
\n" ); document.write( "10+16+22<50
\n" ); document.write( "48<50 SO 10,16&22 ARE ALSO ACCEPTABLE NUMBERS.
\n" ); document.write( "THEREFORE THE ACCEPTABLE NUMBERS FOR X ARE ALL NUMBERS BETWEEN -3 & 10:
\n" ); document.write( "-3,-2,-1,0,1,2,3,4,5,6,7,8,9&10 ARE THE ANSWERS FOR X.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "
\n" );