document.write( "Question 1208178: Hi
\n" ); document.write( "Bob bought a pair of shoes. He also spent 1/4 of the remainder of his money on a pair of pants. He had $189 left. If the cost of the pants was 3/7 the cost of the shoes, what is the price of the shoes.
\n" ); document.write( "

Algebra.Com's Answer #846502 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "Hi\r\n" );
document.write( "Bob bought a pair of shoes. He also spent 1/4 of the remainder of his money on a pair of pants.  He had $189 left. If the cost of the pants was 3/7 the cost of the shoes, what is the price of the shoes.\r\n" );
document.write( "\r\n" );
document.write( "Let the amount he started with, and cost of shoes, be A and S, respectively\r\n" );
document.write( "After buying the shoes, he had A - S left\r\n" );
document.write( "                           Amount spent on pants: \"matrix%281%2C5%2C+1%2F4%2C+of%2C+A+-+S%2C+%22=%22%2C+%28A+-+S%29%2F4%29\" \r\n" );
document.write( "        Amount remaining after purchase of pants: \"matrix%281%2C5%2C+3%2F4%2C+of%2C+A+-+S%2C+%22=%22%2C+3%28A+-+S%29%2F4%29\"\r\n" );
document.write( "Since $189 remained after purchase of pants, we get: \r\n" );
document.write( "                                                       \"matrix%281%2C3%2C+%28A+-+S%29%2F4%2C+%22=%22%2C+63%29\" ------ Canceling GCF, 3, in numerators                                                                            \r\n" );
document.write( "Since cost of pants is \"3%2F7\" the cost of the shoes (S), so we get: \"matrix%281%2C3%2C+%28A+-+S%29%2F4%2C+%22=%22%2C+3S%2F7%29\"  \r\n" );
document.write( "                                                                   \"matrix%281%2C3%2C+63%2C+%22=%22%2C+3S%2F7%29\" ----- Substituting 63 for \"%28A+-+S%29%2F4\"\r\n" );
document.write( "                                                                    3S = 7(63) --- Cross-multiplying\r\n" );
document.write( "                                                  Cost of shoes, or 
\n" ); document.write( "
\n" );