document.write( "Question 1208214: if dy/dx = sec(x) , dt/dx = tan(x) - 3, then ,(d ^2 y)/(dt ^2) =... when(x = 0 \n" ); document.write( "
Algebra.Com's Answer #846495 by mccravyedwin(407)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"dy%2Fdt\"\"%22%22=%22%22\"\"expr%28%28dy%29%2F%28dx%29%29%2Fexpr%28%28dt%29%2F%28dx%29%29\"\"%22%22=%22%22\"\"sec%5E%22%22%28x%29%2F%28tan%5E%22%22%28x%29-3%29\"\r\n" );
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document.write( "\"d%5E2y%2Fdt%5E2\"\"%22%22=%22%22\"\r\n" );
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document.write( "Substitute x = 0\r\n" );
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document.write( "sec(0) = 1, tan(0) = 0\r\n" );
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document.write( "\"dx%2Fdt\"\"%22%22=%22%22\"\"tan%28x%29-3\", substitute x=0, get -3,\r\n" );
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document.write( "So \"dt%2Fdx\"\"%22%22=%22%22\"\"-1%2F3\" when x=0\r\n" );
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document.write( "\"%28%280-3%29%2A1%2A0%2A%28-1%2F3%29+-1%281%29%2A%28-1%2F3%29%29%2F%280-3%29%5E2\"\"%22%22=%22%22\"\"1%2F27\"\r\n" );
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document.write( "Edwin
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