document.write( "Question 1208202: Hi
\n" ); document.write( "There were 1081 visitors at a museum. 3/7 of the female visitors and 1/4 of the male visitors were children. If the number of female adults was 1/3 of the number of male adults, how many adult visitors were at the museum.
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Algebra.Com's Answer #846464 by ikleyn(52798)\"\" \"About 
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\n" ); document.write( "There were 1081 visitors at a museum.
\n" ); document.write( "3/7 of the female visitors and 1/4 of the male visitors were children.
\n" ); document.write( "If the number of female adults was 1/3 of the number of male adults,
\n" ); document.write( "how many adult visitors were at the museum.
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document.write( "Let 7x be the number of female visitors and 4y be the number of male visitors.\r\n" );
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document.write( "Then 3x is the number of girls and 4x is the number of adult females;\r\n" );
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document.write( "      y is the number of boys and 3y is the number of adult males.\r\n" );
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document.write( "Equations:\r\n" );
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document.write( "    7x + 4y = 1081,    (1)\r\n" );
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document.write( "    \"%281%2F3%29%2A3y\" = 4x,     (2)\r\n" );
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document.write( "Equation (2) is the same as\r\n" );
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document.write( "    y = 4x.           (2')\r\n" );
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document.write( "Substitute (2') into (1)\r\n" );
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document.write( "    7x + 4*(4x) = 1081\r\n" );
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document.write( "    7x + 16x    = 1081\r\n" );
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document.write( "      23x       = 1081\r\n" );
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document.write( "        x       = 1081/23 = 47.\r\n" );
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document.write( "Hence,  y = 4*47 = 188.\r\n" );
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document.write( "ANSWER. The number of adult visitors was 4x + 3y = 4*47 + 3*188 = 752.\r\n" );
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