document.write( "Question 1208101: A math assessment question I need to understand.\r
\n" );
document.write( "\n" );
document.write( "Logan is making chocolate chip cookies. He found a recipe that makes
\n" );
document.write( "40 cookies and calls for 1 and 1/3 cups of chocolate chips. If he
\n" );
document.write( "wants to make 70 cookies, which equation correctly calculates how
\n" );
document.write( "many cups of chocolate chips Logan will need?\r
\n" );
document.write( "\n" );
document.write( "a). 1 and 3/4 x 1 and 1/3 = 15/12 = 1 and 1/4 cups\r
\n" );
document.write( "\n" );
document.write( "b). 1 and 1/2 x 1 and 1/3 = 12/6 = 2 cups\r
\n" );
document.write( "\n" );
document.write( "c). 1 and 4/7 x 1 and 1/3 = 44/21 = 2 and 2/21 cups\r
\n" );
document.write( "\n" );
document.write( "d). 1 and 3/4 x 1 and 1/3 = 28/12 = 2 and 1/3 cups \n" );
document.write( "
Algebra.Com's Answer #846411 by math_tutor2020(3816)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: choice D \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Explanation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The recipe Logan found yields 40 cookies. \n" ); document.write( "He instead wants 70 cookies. \n" ); document.write( "70/40 = 7/4 = 1 & 3/4 is the ratio or scale factor we need to apply to scale up the recipe.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "As a simpler example, let's say he wanted to make 80 cookies. That means he'd need to double each portion since 80/40 = 2. \n" ); document.write( "Or if he wanted 120 cookies, then he needs to triple each ingredient since 120/40 = 3. \n" ); document.write( "And so on.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Anyways back to 1 & 3/4. \n" ); document.write( "Based on this value, the answer is between choices A and D.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1 & 3/4 = 7/4 \n" ); document.write( "1 & 1/3 = 4/3 \n" ); document.write( "(7/4)*(4/3) = (7*4)/(4*3) = 28/12 = 7/3 = 2 & 1/3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The result 28/12, along with 2 & 1/3, point us to choice D as the final answer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Another approach would be to use a calculator \n" ); document.write( "(7/4)*(4/3) = 2.3333... where the 3's go on forever. \n" ); document.write( "This matches with 2 & 1/3 = 2 + (1/3) = 2 + 0.3333... = 2.3333...\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "which helps confirm that the answer is choice D \n" ); document.write( " \n" ); document.write( " |