document.write( "Question 1208172: P and Q are two stations. Train A started from P
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document.write( "towards Q at 6:00 a.m at 90 kmph. At the same
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document.write( "time, train B started from R, an intermediate station
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document.write( "60 km from P, and travelled towards Q at 60 kmph.
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document.write( "Train C started from Q towards P at 7:00 a.m at
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document.write( "120 kmph. All the trains crossed each other
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document.write( "simultaneously. Find PQ (in km) \n" );
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Algebra.Com's Answer #846398 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Trains A and B both started at the same time going in the same direction at different speeds, with B having a \"head start\" of 60km. \n" ); document.write( "Train A catches up to train B at a rate equal to the difference of their speeds -- at 30km each hour. \n" ); document.write( "Since train A catches up to train B at a rate of 30km each hour, and since it needs to make up a distance of 60km, the number of hours it takes train A to catch up to train B is 60/30 = 2. \n" ); document.write( "So when train A catches up to train B, it has traveled 2 hours at 90km/h, a distance of 180km; train B started 60km from P and traveled 2 hours at 60km/h, putting it at a distance of 60+2(60) = 180km from P. \n" ); document.write( "Train C started from Q and headed towards P at 120km/h. I started 1 hour later that the other two trains, so it traveled 1 hour at 120km/h, a distance of 120km. \n" ); document.write( "Trains A, B, and C reached the same place at the same time. At that time, trains A and B were 180km from P and train C was 120km from Q. So the distance from P to Q was 180+120 = 300km. \n" ); document.write( "ANSWER: 300km \n" ); document.write( " \n" ); document.write( " |