document.write( "Question 1208158: A rectangle given is a golden rectangle.\r
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\n" ); document.write( "\n" ); document.write( "Rectangle BCDE is similar to rectangle ACDF.\r
\n" ); document.write( "\n" ); document.write( "a. Show that \r
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\n" ); document.write( " b. Find the exact value of a(which will give you the golden ratio) by completing the square.
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Algebra.Com's Answer #846379 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "We can't tell which rectangle is given as a golden rectangle. Plus, you\r\n" );
document.write( "didn't tell us what \" a \", and what, if anything, you are letting be 1.\r\n" );
document.write( "Probably English is not your first language.  That is OK!! It is my ONLY\r\n" );
document.write( "language. J\r\n" );
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document.write( "I will assume that rectangle ACDF is given as a golden rectangle, and I will\r\n" );
document.write( "assume that the length of a side of square ABEF is \" a \". the shorter side of\r\n" );
document.write( "rectangle BCDE is given as \" 1 \".  \r\n" );
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document.write( "By definition of 'golden rectangle':\r\n" );
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document.write( "\"matrix%281%2C2%2CSHORT%2CSIDE%29%2Fmatrix%281%2C2%2CLONG%2CSIDE%29\"\"%22%22=%22%22\"\r\n" );
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document.write( "\"AF%2FAC\"\"%22%22=%22%22\"\"AC%2F%28AF%2BAC%29\"\r\n" );
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Rectangle BCDE is similar to rectangle ACDF.
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document.write( "\"matrix%281%2C4%2CSHORT%2CSIDE%2COF%2CBCDE%29%2Fmatrix%281%2C4%2CSHORT%2CSIDE%2COF%2CACDF%29\"\"%22%22=%22%22\"\"matrix%281%2C4%2CLONG%2CSIDE%2COF%2CBCDE%29%2Fmatrix%281%2C4%2CLONG%2CSIDE%2COF%2CACDF%29\"\r\n" );
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a. Show that
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document.write( "\"BC%2FAF\"\"%22%22=%22%22\"\"BE%2FAC\"\r\n" );
document.write( "\"1%2Fa\"\"%22%22=%22%22\"\"a%2F%28a%2B1%29\"\r\n" );
document.write( "CROSS-MULTIPLY\r\n" );
document.write( "\"a%5E2\"\"%22%22=%22%22\"\"a%2B1\"\r\n" );
document.write( "\"a%5E2-a\"\"%22%22=%22%22\"\"1\"  <-- use this in part (b)\r\n" );
document.write( "\"a%28a-1%29\"\"%22%22=%22%22\"\"1\"\r\n" );
document.write( "Divide both sides by (a-1)\r\n" );
document.write( "\"%28a%28a-1%29%29%2F%28a-1%29\"\"%22%22=%22%22\"\"1%2F%28a-1%29\"\r\n" );
document.write( "\"%28a%28cross%28a-1%29%29%29%2F%28cross%28a-1%29%29\"\"%22%22=%22%22\"\"1%2F%28a-1%29\"\r\n" );
document.write( "\"a%2F1\"\"%22%22=%22%22\"\"1%2F%28a-1%29\"\r\n" );
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b. Find the exact value of a(which will give you the golden ratio) by completing the square.
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document.write( "\"a%5E2-a\"\"%22%22=%22%22\"\"1\"\r\n" );
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document.write( "1. Get half of coefficient of a:   (-1)/2 = -1/2\r\n" );
document.write( "2. Square (-1/2), get +1/4\r\n" );
document.write( "3. Add to both sides\r\n" );
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document.write( "\"a%5E2-a%2B1%2F4\"\"%22%22=%22%22\"\"1%2B1%2F4\"\r\n" );
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document.write( "Factor left side into the square of a binomial:\r\n" );
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document.write( "\"%28a-1%2F2%29%28a-1%2F2%29\"\"%22%22=%22%22\"\"5%2F4\"\r\n" );
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document.write( "\"%28a-1%2F2%29%5E2\"\"%22%22=%22%22\"\"5%2F4\"\r\n" );
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document.write( "Take square roots of both sides, using ± on right.\r\n" );
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document.write( "\"sqrt%28%28a-1%2F2%29%5E2%29\"\"%22%22=%22%22\"\"%22%22+%2B-+sqrt%285%2F4%29\"\r\n" );
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document.write( "\"a-1%2F2\"\"%22%22=%22%22\"\"%22%22+%2B-+sqrt%285%29%2F2\"\r\n" );
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document.write( "\"a\"\"%22%22=%22%22\"\"1%2F2+%2B-+sqrt%285%29%2F2\"\r\n" );
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document.write( "\"a\"\"%22%22=%22%22\"\"%281+%2B-+sqrt%285%29%29%2F2\"\r\n" );
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document.write( "Since ' a ' is not negative, we discard the - sign:\r\n" );
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document.write( "\"a\"\"%22%22=%22%22\"\"%281+%2B+sqrt%285%29%29%2F2\"\r\n" );
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document.write( "That is the exact value of ' a ', the golden ratio.\r\n" );
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document.write( "Edwin
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