document.write( "Question 1208118: A circular disc of cast iron is 7 ft. in diameter and 1 1/3 in. thick. Determine weight. \r
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document.write( "A plate 1 ft. square and 1 in. thick weighs 37.5 lbs.\r
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document.write( "Area of circle: pi * r^2.\r
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document.write( "Not sure how to solve. \n" );
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Algebra.Com's Answer #846301 by greenestamps(13203)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The methods shown by the other tutors are fine. \n" ); document.write( "Here is another.... \n" ); document.write( "Start with the 37.5 pounds that the plate, 1 foot square and 1 inch thick, weighs. \n" ); document.write( "The cross sectional area of the plate is 1 square foot. \n" ); document.write( "The cross sectional area of the disc is \n" ); document.write( "The cross sectional area of the disc is greater than the cross sectional area of the plate by a factor of \n" ); document.write( "The thickness of the plate is 1 inch; the thickness of the disc is 1 1/3 inches. \n" ); document.write( "The disc is thicker than the plate by a factor of 1 1/3 = 4/3. \n" ); document.write( "Multiply the weight of the plate by the factors by which the cross sectional area and thickness of the disc exceed those of the plate: \n" ); document.write( "ANSWER: \n" ); document.write( " \n" ); document.write( " |