document.write( "Question 1208118: A circular disc of cast iron is 7 ft. in diameter and 1 1/3 in. thick. Determine weight. \r
\n" ); document.write( "\n" ); document.write( "A plate 1 ft. square and 1 in. thick weighs 37.5 lbs.\r
\n" ); document.write( "\n" ); document.write( "Area of circle: pi * r^2.\r
\n" ); document.write( "\n" ); document.write( "Not sure how to solve.
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Algebra.Com's Answer #846301 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "The methods shown by the other tutors are fine.

\n" ); document.write( "Here is another....

\n" ); document.write( "Start with the 37.5 pounds that the plate, 1 foot square and 1 inch thick, weighs.

\n" ); document.write( "The cross sectional area of the plate is 1 square foot.
\n" ); document.write( "The cross sectional area of the disc is \"%28pi%29%28r%5E2%29=%28pi%29%287%2F2%29%5E2=%2849%2F4%29pi\".
\n" ); document.write( "The cross sectional area of the disc is greater than the cross sectional area of the plate by a factor of \"%2849%2F4%29pi\"

\n" ); document.write( "The thickness of the plate is 1 inch; the thickness of the disc is 1 1/3 inches.
\n" ); document.write( "The disc is thicker than the plate by a factor of 1 1/3 = 4/3.

\n" ); document.write( "Multiply the weight of the plate by the factors by which the cross sectional area and thickness of the disc exceed those of the plate:

\n" ); document.write( "ANSWER: \"%2837.5%29%28%2849%2F4%29pi%29%284%2F3%29\" = 612.5pi = 1924 to the nearest whole number.

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