document.write( "Question 1208118: A circular disc of cast iron is 7 ft. in diameter and 1 1/3 in. thick. Determine weight. \r
\n" ); document.write( "\n" ); document.write( "A plate 1 ft. square and 1 in. thick weighs 37.5 lbs.\r
\n" ); document.write( "\n" ); document.write( "Area of circle: pi * r^2.\r
\n" ); document.write( "\n" ); document.write( "Not sure how to solve.
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Algebra.Com's Answer #846291 by ikleyn(52847)\"\" \"About 
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A circular disc of cast iron is 7 ft. in diameter and 1 1/3 in. thick. Determine weight. \r
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\n" ); document.write( "\n" ); document.write( "Area of circle: pi * r^2.
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document.write( "              Step by step\r\n" );
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document.write( "(1)  Convert 7 ft to inches: 7 ft = 7*12 = 84 inches.\r\n" );
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document.write( "(2)  Find the area of the circular disk in square inches using the formula.\r\n" );
document.write( "     Remember that the radius is half of the diameter.\r\n" );
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document.write( "(3)  Find the volume of the circular disk in cubic inches by multiplying its area \r\n" );
document.write( "     by the thick, which is 4/3 inches.\r\n" );
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document.write( "(4)  Find the density of the iron in  \"lbs%2Fin%5E3\"  by dividing 37.5 lbs by the area \r\n" );
document.write( "     of 1 ft by 1 ft plate, which is 12*12 = 144 square inches.\r\n" );
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document.write( "(5)  To find weight, multiply the volume found in (3) by the density found in (4).\r\n" );
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\n" ); document.write( "\n" ); document.write( "comment from student: Please check my calculations :
\n" ); document.write( "1) 84 in. 2) 3.1416 * 42 * 42 = 5541.78 = 5542 in.^2 3) 5542 * 1.333 = 7380 in.^3
\n" ); document.write( "4) 37.5 / 144 = .2604 lbs. / ft.^3 5) 7389 * .2604 = 1924.09 = 1924 lbs\r
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\n" ); document.write( "\n" ); document.write( "My response :   I checked your calculations.   They are correct.\r
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\n" ); document.write( "\n" ); document.write( "I am very impressed.   My congratulations  !   You made great job  !\r
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