document.write( "Question 1208108: The wind chill factor represents the equivalent air temperature at a standard wind speed that would produce the same heat loss as the given temperature and wind speed. One formula for computing the equivalent temperature is given below.\r
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\n" ); document.write( "\n" ); document.write( "Let W = a piecewise function. \r
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\n" ); document.write( "\n" ); document.write( "Top portion: t if 0 <= v < 1.79\r
\n" ); document.write( "\n" ); document.write( "Middle portion: \r
\n" ); document.write( "\n" ); document.write( "33 - [(10.45 + 10sqrt{v} - v)(33 - t)]/(22.04)
\n" ); document.write( "if 1.79 <= v <= 20\r
\n" ); document.write( "\n" ); document.write( "Bottom portion: 33 - 1.5958(33 - t) if v > 20\r
\n" ); document.write( "\n" ); document.write( "where v represents the wind speed (in meters per second) and t represents the air temperature (°C). \r
\n" ); document.write( "\n" ); document.write( "Compute the wind chill for the following: \r
\n" ); document.write( "\n" ); document.write( "(a) An air temperature of 10°C and a wind speed of 5 m/sec\r
\n" ); document.write( "\n" ); document.write( "(b) An air temperature of 10°C and a wind speed of 25 m/sec
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Algebra.Com's Answer #846277 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Piecewise functions can be a strange beast.
\n" ); document.write( "I think of them as a Frankenstein's monster because we glue together various parts of other functions. \r
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\n" ); document.write( "\n" ); document.write( "The function will change its identity based on what the input is.
\n" ); document.write( "The input in this case is variable v (t is the parameter and appears to be fixed to t = 10).\r
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\n" ); document.write( "\n" ); document.write( "We have 3 scenarios
  • If 0 <= v < 1.79, then W(v) = t
  • If 1.79 <= v <= 20, then W(v) = 33 - (10.45 + 10*sqrt(v) - v)*(33-t)/22.04
  • If v > 20, then W(v) = 33 - 1.5958(33-t)
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\n" ); document.write( "\n" ); document.write( "Part (a)\r
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\n" ); document.write( "\n" ); document.write( "t = 10
\n" ); document.write( "v = 5\r
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\n" ); document.write( "\n" ); document.write( "v = 5 fits the interval 1.79 <= v <= 20, so we use the middle piece.\r
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\n" ); document.write( "\n" ); document.write( "W(v) = 33 - (10.45 + 10*sqrt(v) - v)*(33-t)/22.04
\n" ); document.write( "W(5) = 33 - (10.45 + 10*sqrt(5) - 5)*(33-10)/22.04
\n" ); document.write( "W(5) = 3.977965752044
\n" ); document.write( "W(5) = 3.98
\n" ); document.write( "The wind chill is approximately 3.98 degrees Celsius.\r
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\n" ); document.write( "\n" ); document.write( "Part (b)\r
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\n" ); document.write( "\n" ); document.write( "This time we have
\n" ); document.write( "t = 10
\n" ); document.write( "v = 25\r
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\n" ); document.write( "\n" ); document.write( "v = 25 fits the interval v > 20 aka 20 < v < infinity.
\n" ); document.write( "So we'll use the 3rd piece of this piecewise function.\r
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\n" ); document.write( "\n" ); document.write( "W(v) = 33 - 1.5958(33-t)
\n" ); document.write( "W(25) = 33 - 1.5958(33-10)
\n" ); document.write( "W(25) = -3.7034
\n" ); document.write( "The wind chill is roughly -3.7034 degrees Celsius.\r
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\n" ); document.write( "\n" ); document.write( "Side notes:
\n" ); document.write( "10 degrees Celsius = 50 degrees Fahrenheit
\n" ); document.write( "3.98 degrees Celsius = 39.164 degrees Fahrenheit
\n" ); document.write( "-3.7034 degrees Celsius = 25.33388 degrees Fahrenheit
\n" ); document.write( "5 m/s = 18 km/hr = 11.1846815 mph
\n" ); document.write( "25 m/s = 90 km/hr = 55.9234073 mph
\n" ); document.write( "The decimal values are approximate.
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