document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1208108>Question 1208108</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The wind chill factor represents the equivalent air temperature at a standard wind speed that would produce the same heat loss as the given temperature and wind speed. One formula for computing the equivalent temperature is given below.\r<BR>\n" );
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document.write( "Let W = a piecewise function. \r<BR>\n" );
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document.write( "Top portion: t if 0 <= v < 1.79\r<BR>\n" );
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document.write( "Middle portion: \r<BR>\n" );
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document.write( "33 - [(10.45 + 10sqrt{v} - v)(33 - t)]/(22.04) <BR>\n" );
document.write( "if 1.79 <= v <= 20\r<BR>\n" );
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document.write( "Bottom portion: 33 - 1.5958(33 - t) if v > 20\r<BR>\n" );
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document.write( "where v represents the wind speed (in meters per second) and t represents the air temperature (°C). \r<BR>\n" );
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document.write( "Compute the wind chill for the following: \r<BR>\n" );
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document.write( "(a) An air temperature of 10°C and a wind speed of 5 m/sec\r<BR>\n" );
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document.write( "(b) An air temperature of 10°C and a wind speed of 25 m/sec </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #846274 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=846274\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a. 33- (10.45+10sqrt(5)-5)(23)/22.04) =33-29.02 or 3.98 C (4 C)<BR>\n" );
document.write( "b. 33-1.5958(23)=-3.70 C. </SPAN>\n" );
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