document.write( "Question 1208080: Marks of 75 students are summarized in the following frequency distribution,\r
\n" ); document.write( "\n" ); document.write( "Marks Number of students
\n" ); document.write( "40-44 7
\n" ); document.write( "45-49 10
\n" ); document.write( "50-54 20
\n" ); document.write( "55-59 f4
\n" ); document.write( "60-64 f5
\n" ); document.write( "65-69 6
\n" ); document.write( "70-74 3\r
\n" ); document.write( "\n" ); document.write( "If 20% of the students have marks between 55 and 59\r
\n" ); document.write( "\n" ); document.write( "i. Find the missing frequencies f4 and 15.\r
\n" ); document.write( "\n" ); document.write( "ii. Find the mean.
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Algebra.Com's Answer #846238 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Part (i)\r
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\n" ); document.write( "\n" ); document.write( "Original table
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MarksNumber of students
40-447
45-4910
50-5420
55-59f4
60-64f5
65-696
70-743

\n" ); document.write( "Spreadsheet software is strongly recommended.\r
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\n" ); document.write( "\n" ); document.write( "20% of 75 = 0.20*75 = 15 students have marks between 55 and 59.
\n" ); document.write( "This means f4 = 15.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Add up the frequencies in the 2nd column.
\n" ); document.write( "Set this sum equal to 75 so we can determine the value of f5.
\n" ); document.write( "7+10+20+f4+f5+6+3 = 75
\n" ); document.write( "7+10+20+15+f5+6+3 = 75
\n" ); document.write( "61+f5 = 75
\n" ); document.write( "f5 = 75-61
\n" ); document.write( "f5 = 14\r
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\n" ); document.write( "\n" ); document.write( "Part (ii)\r
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\n" ); document.write( "\n" ); document.write( "In the previous part we found that
\n" ); document.write( "f4 = 15 and f5 = 14\r
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\n" ); document.write( "\n" ); document.write( "After replacing f4 and f5 with those values, we now have this grouped frequency table.
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "
MarksNumber of students
40-447
45-4910
50-5420
55-5915
60-6414
65-696
70-743

\n" ); document.write( "Let's introduce a new column which I'll refer to as column m.
\n" ); document.write( "m = midpoint of the corresponding class interval
\n" ); document.write( "To find the midpoint, add the endpoints and divide by 2.
\n" ); document.write( "Example: m = 42 for the first class since (40+44)/2 = 42\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Here's what the table looks like now
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MarksNumber of studentsm
40-44742
45-491047
50-542052
55-591557
60-641462
65-69667
70-74372

\n" ); document.write( "The midpoint is the best representative mark from each class interval.
\n" ); document.write( "Multiply the frequency value (f) with its corresponding midpoint (m).
\n" ); document.write( "This will form a new column which I'll label as f*m.
\n" ); document.write( "For example, f*m = 7*42 = 294 is the first item in this new column.\r
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MarksNumber of studentsM = midpointf*m
40-44742294
45-491047470
50-5420521040
55-591557855
60-641462868
65-69667402
70-74372216

\n" ); document.write( "Add up the values in this new column to get
\n" ); document.write( "294+470+1040+855+868+402+216 = 4145\r
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\n" ); document.write( "\n" ); document.write( "Then divide this over the total number of people (75) to get 4145/75 = 55.266667 which is the approximate mean.
\n" ); document.write( "The 6's go on forever but we have to round at some point.\r
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\n" ); document.write( "\n" ); document.write( "Answers:
  1. f4 = 15 and f5 = 14
  2. mean = 55.266667 approximately

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