document.write( "Question 1208080: Marks of 75 students are summarized in the following frequency distribution,\r
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document.write( "Marks Number of students
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document.write( "40-44 7
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document.write( "45-49 10
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document.write( "50-54 20
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document.write( "55-59 f4
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document.write( "60-64 f5
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document.write( "65-69 6
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document.write( "70-74 3\r
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document.write( "If 20% of the students have marks between 55 and 59\r
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document.write( "i. Find the missing frequencies f4 and 15.\r
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document.write( "ii. Find the mean. \n" );
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Algebra.Com's Answer #846238 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Part (i)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Original table \n" ); document.write( "
\n" ); document.write( "Spreadsheet software is strongly recommended.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "20% of 75 = 0.20*75 = 15 students have marks between 55 and 59. \n" ); document.write( "This means f4 = 15.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add up the frequencies in the 2nd column. \n" ); document.write( "Set this sum equal to 75 so we can determine the value of f5. \n" ); document.write( "7+10+20+f4+f5+6+3 = 75 \n" ); document.write( "7+10+20+15+f5+6+3 = 75 \n" ); document.write( "61+f5 = 75 \n" ); document.write( "f5 = 75-61 \n" ); document.write( "f5 = 14\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Part (ii)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In the previous part we found that \n" ); document.write( "f4 = 15 and f5 = 14\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "After replacing f4 and f5 with those values, we now have this grouped frequency table. \n" ); document.write( "
\n" ); document.write( "Let's introduce a new column which I'll refer to as column m. \n" ); document.write( "m = midpoint of the corresponding class interval \n" ); document.write( "To find the midpoint, add the endpoints and divide by 2. \n" ); document.write( "Example: m = 42 for the first class since (40+44)/2 = 42\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here's what the table looks like now \n" ); document.write( "
\n" ); document.write( "The midpoint is the best representative mark from each class interval. \n" ); document.write( "Multiply the frequency value (f) with its corresponding midpoint (m). \n" ); document.write( "This will form a new column which I'll label as f*m. \n" ); document.write( "For example, f*m = 7*42 = 294 is the first item in this new column.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "Add up the values in this new column to get \n" ); document.write( "294+470+1040+855+868+402+216 = 4145\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then divide this over the total number of people (75) to get 4145/75 = 55.266667 which is the approximate mean. \n" ); document.write( "The 6's go on forever but we have to round at some point.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answers:
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