document.write( "Question 1207918: For A and B, find the standard form of the equation of each circle.\r
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Algebra.Com's Answer #846204 by MathTherapy(10552)\"\" \"About 
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document.write( "For A and B, find the standard form of the equation of each circle.\r\n" );
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document.write( "A. Center (1,0) and has the point (-3,2).\r\n" );
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document.write( "B. Center (-3,1) and tangent to the y-axis.\r\n" );
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document.write( "Standard form of the equation of a circle: \"matrix%281%2C3%2C+%28x+-+h%29%5E2+%2B+%28y+-+k%29%5E2%2C+%22=%22%2C+r%5E2%29\", where: \"%22%28x%2C+y%29%22\" is a point on the circle's circumference\r\n" );
document.write( "                                                                         \"%22%28h%2C+k%29%22\" is the CENTER of the circle\r\n" );
document.write( "                                                                         \"r\" is the circle's RADIUS\r\n" );
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document.write( "  \"matrix%281%2C3%2C+%28x+-+h%29%5E2+%2B+%28y+-+k%29%5E2%2C+%22=%22%2C+r%5E2%29\"\r\n" );
document.write( "\"matrix%281%2C3%2C+%28-+3+-+1%29%5E2+%2B+%282+-+0%29%5E2%2C+%22=%22%2C+r%5E2%29\" ----- Substituting (- 3, 2) for (x, y), and (1, 0) for (h, k)\r\n" );
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document.write( "  \"matrix%281%2C3%2C+%28x+-+h%29%5E2+%2B+%28y+-+k%29%5E2%2C+%22=%22%2C+r%5E2%29\" <==== Standard form of the equation of a circle \r\n" );
document.write( "  \"matrix%281%2C3%2C+%28x+-+1%29%5E2+%2B+%28y+-+0%29%5E2%2C+%22=%22%2C+20%29\" ----- Substituting (1, 0) for (h, k), and 20 for r2\r\n" );
document.write( "      \"highlight_green%28matrix%281%2C3%2C+%28x+-+1%29%5E2+%2B+y%5E2%2C+%22=%22%2C+20%29%29\" <=== Standard form of the equation of the circle with center (1,0) and point (-3,2) on its circumference
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