document.write( "Question 1208053: For h(x) = -2x^2 + x, \r
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Algebra.Com's Answer #846194 by Edwin McCravy(20055) $\"\"$ $\"About$

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document.write( "For h(x) = -2x^2 + x, \r\n" );
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document.write( "A. Find the average rate of change from 0 to .As x goes from 0 to 3, y [or h(x)] goes from h(0)=-2(0)^2 + 0=0 to h(3)=-2(3)^2 + (3)=-15\r\n" );
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document.write( "From 0 to -15 is a change of (-15)-(0)=-15 in y\r\n" );
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document.write( "From 0 to 3 is a change of (3)-(0) = +3 in x\r\n" );
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document.write( "So the average change in y [or h(x)] per the +3 average change in x\r\n" );
document.write( "is -15 units change in y per a +3 change in x, which means an average\r\n" );
document.write( "change of (-15)/(+3)=-5 y-units change per x-units change.\r\n" );
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document.write( "That's what the slope is, the change in y, divided by the change in x \r\n" );
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document.write( "Answer: -5 change in h(x) y-units per x-unit change.
B. Find an equation of the secant line containing (0, h(0)) and (3, h(3)).\r\n" );
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document.write( "change y to h(x)\r\n" );
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document.write( "The black line is the secant line. It has two points\r\n" );
document.write( "in common with the function h(x) (the red curve).\r\n" );
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document.write( "Remember what the word \"secant\" means, a line that cuts\r\n" );
document.write( "through a curve, as you can see, the black line cuts through\r\n" );
document.write( "the red curve, which is the graph of y = h(x). \r\n" );
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document.write( "[Remember from your geometry that a secant line was a line\r\n" );
document.write( "that cuts through a circle.] \r\n" );
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document.write( "Edwin \n" );
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