document.write( "Question 1208045: Mr B invested p30000:part at 5% and part at 8%.The total interest on the investment was p2100. How much did she invest at each rate. \n" ); document.write( "
Algebra.Com's Answer #846177 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "First a typical formal algebraic solution.... \n" ); document.write( "x = amount invested at 5% \n" ); document.write( "30000-x = amount invested at 8% \n" ); document.write( "The total interest earned was 2100: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWERS: \n" ); document.write( "x = p10000 invested at 5% \n" ); document.write( "30000-x = p20000 invested at 8% \n" ); document.write( "And then a fast and easy informal method for solving any 2-part \"mixture\" problem like this.... \n" ); document.write( "2100 interest on an investment of 30000 is an interest rate of 2100/30000 = .07 = 7% \n" ); document.write( "7% is 2/3 of the way from 5% to 8% (look at the three numbers 5, 7, and 8 on a number line if it helps) \n" ); document.write( "That means 2/3 of the total p30000 was invested at the higher rate \n" ); document.write( "ANSWERS: \n" ); document.write( "2/3 of p30000 = p20000 invested at 8% \n" ); document.write( "1/3 of p30000 = p10000 invested at 5% \n" ); document.write( " \n" ); document.write( " |