document.write( "Question 1208045: Mr B invested p30000:part at 5% and part at 8%.The total interest on the investment was p2100. How much did she invest at each rate. \n" ); document.write( "
Algebra.Com's Answer #846177 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "First a typical formal algebraic solution....

\n" ); document.write( "x = amount invested at 5%
\n" ); document.write( "30000-x = amount invested at 8%

\n" ); document.write( "The total interest earned was 2100:

\n" ); document.write( "\".05%28x%29%2B.08%2830000-x%29=2100\"
\n" ); document.write( "\".05x%2B2400-.08x=2100\"
\n" ); document.write( "\"-.03x=-300\"
\n" ); document.write( "\"x=300%2F.03=10000\"

\n" ); document.write( "ANSWERS:
\n" ); document.write( "x = p10000 invested at 5%
\n" ); document.write( "30000-x = p20000 invested at 8%

\n" ); document.write( "And then a fast and easy informal method for solving any 2-part \"mixture\" problem like this....

\n" ); document.write( "2100 interest on an investment of 30000 is an interest rate of 2100/30000 = .07 = 7%
\n" ); document.write( "7% is 2/3 of the way from 5% to 8% (look at the three numbers 5, 7, and 8 on a number line if it helps)
\n" ); document.write( "That means 2/3 of the total p30000 was invested at the higher rate

\n" ); document.write( "ANSWERS:
\n" ); document.write( "2/3 of p30000 = p20000 invested at 8%
\n" ); document.write( "1/3 of p30000 = p10000 invested at 5%

\n" ); document.write( "
\n" ); document.write( "
\n" );