document.write( "Question 116381: Find two consecutive odd integers such that three times the second is twelve more than the first. \n" ); document.write( "

Algebra.Com's Answer #84617 by MathLover1(20849) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Find two consecutive odd integers such that three times the second is twelve more than the first.\r
\n" ); document.write( "\n" ); document.write( "let two consecutive odd be:\r
\n" ); document.write( "\n" ); document.write( " $\"x\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x%2B+2\"$ \r
\n" ); document.write( "\n" ); document.write( "three times the second is twelve more than the first, then\r
\n" ); document.write( "\n" ); document.write( " $\"3%28x%2B+2%29+=+x+%2B+12\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3x%2B+6+=+x+%2B+12\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3x+-+x+=+12+-+6\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2x+=+6\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x+=+3\"$ ЕЕЕ.first odd number
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\n" ); document.write( " $\"x%2B+2=+5\"$ ЕЕsecond odd number\r
\n" ); document.write( "\n" ); document.write( "Check if
\n" ); document.write( "three times the second is twelve more than the first\r
\n" ); document.write( "\n" ); document.write( " $\"3%2A5+=+3%2B12\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"15+=+15\"$
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