document.write( "Question 1208012: Suppose that a word-association experiment is conducted using eight people as blocks and making a comparison of reaction times within each person; that is, each person is subjected to both stimuli in a random order. The reaction times (in seconds) for the experiment are as follows.
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document.write( "Person__________Stimulus 1__________Stimulus 2 (IGNORE THE LINES - space)
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document.write( "1__________________2__________________5 (IGNORE THE LINES - space)
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document.write( "2__________________1__________________3 (IGNORE THE LINES - space)
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document.write( "3__________________1__________________4 (IGNORE THE LINES - space)
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document.write( "4__________________2__________________2 (IGNORE THE LINES - space)
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document.write( "5__________________1__________________3 (IGNORE THE LINES - space)
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document.write( "6__________________2__________________3 (IGNORE THE LINES - space)
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document.write( "7__________________3__________________4 (IGNORE THE LINES - space)
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document.write( "8__________________2__________________3 (IGNORE THE LINES - space)\r
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document.write( "Do the data present sufficient evidence to indicate a difference in mean reaction times for the two stimuli? Test using 𝛼 = 0.05. (Use 𝜇1 − 𝜇2 = 𝜇d.)\r
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document.write( "a) State the test statistic. (Round your answer to three decimal places.)
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document.write( "t = __________\r
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document.write( "b) State the rejection region. (If the test is one-tailed, enter NONE for the unused region. Round your answers to three decimal places.)
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document.write( "t > __________
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document.write( "t < ___________
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document.write( "
Algebra.Com's Answer #846155 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answers: \n" ); document.write( "(a) -4.333 \n" ); document.write( "(b) t > 2.365 or t < -2.365 \n" ); document.write( "All decimal values mentioned are approximate.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Part (a)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Given data \n" ); document.write( "
\n" ); document.write( "There are n = 8 people which is the sample size.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract the first two columns to form a new column of values. \n" ); document.write( "
\n" ); document.write( "Example: 2-5 = -3 in the first row of this new column.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add up the values in that new column to get -13. \n" ); document.write( "Divide this sum over the sample size n = 8 to get -13/8 = -1.625 which is the value of xbard \n" ); document.write( "xbar = x with a horizontal bar over top = sample mean \n" ); document.write( "xbar with a subscript \"d\" indicates we're looking at the sample mean of the differences.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you want, you can compute the sample standard deviation of the differences by hand, but it's much better to use technology. \n" ); document.write( "Grab your favorite calculator. I used the spreadsheet's calculator since the data is already in spreadsheet form. \n" ); document.write( "You should find that \n" ); document.write( "sd = 1.06066017 approximately \n" ); document.write( "Caution: Do not mix up sample standard deviation with population standard deviation. You'll be using the sample version.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then, \n" ); document.write( "Test Statistic = (xbard)/( (sd)/sqrt(n) ) \n" ); document.write( "Test Statistic = (-1.625)/( (1.06066017)/sqrt(8) ) \n" ); document.write( "Test Statistic = -4.333333340605 \n" ); document.write( "Test Statistic = -4.333\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------------------------------------------------------------------------- \n" ); document.write( "Part (b)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We're doing a paired T-test. \n" ); document.write( "𝜇 = greek letter mu = population mean \n" ); document.write( "𝜇1 = population mean of stimulus 1. \n" ); document.write( "𝜇2 = population mean of stimulus 2. \n" ); document.write( "𝜇d = 𝜇1-𝜇2 = population mean of the differences.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hypotheses \n" ); document.write( "Null: 𝜇d = 0 \n" ); document.write( "Alternative: 𝜇d =/= 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The alternative hypothesis has the \"not equal\" sign because of the phrasing \"Do the data present sufficient evidence to indicate a difference in mean reaction times for the two stimuli?\" \n" ); document.write( "If the answer to this question was \"no\", then we'd stick with the null. \n" ); document.write( "The \"not equal\" sign in the alternative means we have a two-tailed test.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "As mentioned, we're doing a paired T-test. \n" ); document.write( "We'll be using the T distribution. \n" ); document.write( "n = 8 = sample size \n" ); document.write( "df = degrees of freedom \n" ); document.write( "df = n-1 \n" ); document.write( "df = 8-1 \n" ); document.write( "df = 7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll now use this T table \n" ); document.write( "https://www.sjsu.edu/faculty/gerstman/StatPrimer/t-table.pdf \n" ); document.write( "A similar table should be found in your textbook somewhere. Likely in the back (appendix section). Alternatively you can use a stats calculator such as a TI83.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In that table, highlight the df = 7 row and \"two tail = 0.05\" column. \n" ); document.write( "The 0.05 refers to the alpha value. \n" ); document.write( "This row and column intersect to give us the value 2.365 which is approximate.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It tells us that P(-2.365 < t < 2.365) = 0.95 when df = 7. \n" ); document.write( "i.e. the area under the curve between t = -2.365 and t = 2.365 is roughly 0.95 \n" ); document.write( "This applies only when df = 7. \n" ); document.write( "This corresponds to a 95% confidence interval. \n" ); document.write( "The remaining 1-0.95 = 0.05 is the combined area of both tails.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If the test statistic is in the interval -2.365 < t < 2.365, then we fail to reject the null. \n" ); document.write( "Otherwise the test statistic is in the rejection region and we would reject the null.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore the rejection region is: \n" ); document.write( "t > 2.365 or t < -2.365\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Extra info: \n" ); document.write( "Test Statistic = -4.333 was found earlier in part (a). \n" ); document.write( "It is outside the interval -2.365 < t < 2.365 and fits with t < -2.365 instead. \n" ); document.write( "We're in the rejection region. \n" ); document.write( "This means we'll reject the null. We'll conclude that there appears to be a difference in the reaction times for the two stimuli. \n" ); document.write( " \n" ); document.write( " |