document.write( "Question 116287: How many pounds of hamburger that costs $1.10 per pound must be mixed with 50 pounds of hamburger that costs $1.80 per pound to make a mixture that costs $1.30 per pound?\r
\n" ); document.write( "\n" ); document.write( "I came up with 200. Please tell me if I am correct! \n" ); document.write( "

Algebra.Com's Answer #84612 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
The formula is
\n" ); document.write( "( price per pound #1)(pounds #1) + (price per pound #2)(pounds #2)
\n" ); document.write( "equals (price per pound mixture)(pounds of mixture)
\n" ); document.write( "Let $\"x\"$ equal pounds of $1.10 hamburger
\n" ); document.write( " $\"1.1%2Ax+%2B+1.8%2A50+=+1.3%2850+%2B+x%29\"$
\n" ); document.write( " $\"1.1x+%2B+90+=+65+%2B+1.3%2Ax\"$
\n" ); document.write( " $\".2x+=+25\"$
\n" ); document.write( " $\"2x+=+250\"$
\n" ); document.write( " $\"x+=+125\"$ pounds of #1.10 hamburger answer
\n" ); document.write( "check answer
\n" ); document.write( " $\"1.1%2Ax+%2B+1.8%2A50+=+1.3%2850+%2B+x%29\"$
\n" ); document.write( " $\"1.1%2A125+%2B+1.8%2A50+=+1.3%2850+%2B+125%29\"$
\n" ); document.write( " $\"137.5+%2B+90+=+1.3%2A175\"$
\n" ); document.write( " $\"227.5+=+227.5\"$
\n" ); document.write( "OK \n" ); document.write( "

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