document.write( "Question 1208007: A new ship is being designed to have two types of cabin accommodation for the
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\n" ); document.write( "ii)Using the graphical method find the number of cabins of each type required to maximize the income given that income from one voyage of type A cabin is kSh 6,000 and that of type B cabins is ksh 1,800.
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Algebra.Com's Answer #846116 by Edwin McCravy(20060)\"\" \"About 
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document.write( "Maximize z = 6000x+1800y\r\n" );
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document.write( "subject to constraints\r\n" );
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document.write( "We find the intercepts and draw the lines 6x+3y=330 and 50x+10y=2300\r\n" );
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document.write( "By the inequality symbols, we see the feasible region is on and\r\n" );
document.write( "above the x-axis, on or to the right of the y-axis, and on or below \r\n" );
document.write( "the other two lines.  So we shade the feasible region:\r\n" );
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document.write( "So we evaluate the objective function  z = 6000x+1800y\r\n" );
document.write( "at each corner point of the feasible region.\r\n" );
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document.write( "At (0,0), 6000(0)+1800(0) = 0 kSh\r\n" );
document.write( "At (46,0), 6000(46)+1800(0) = 276,000 kSh\r\n" );
document.write( "At (40,30), 6000(40)+1800(30) = 494,000 kSh\r\n" );
document.write( "At (0,110), 6000(0)+1800(110) = 198,000 kSh\r\n" );
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document.write( "So the maximum profit is 494,000 kSh when there are 40 type A\r\n" );
document.write( "cabins and 30 type B cabins.\r\n" );
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document.write( "Edwin
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