document.write( "Question 1208002: The monthly payment pon a mortgage varies directly with the amount borrowed B. If the monthly payment on a 15-year mortgage is $8.99 for every $1000 borrowed, find a linear equation that relates the monthly payment p to the amount borrowed B for a mortgage with the same terms. Then find the monthly payment p when the amount borrowed B is $175,000. \r
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Algebra.Com's Answer #846105 by mananth(16946)\"\" \"About 
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The monthly payment p varies directly with the amount borrowed B,
\n" ); document.write( "p \"alpha\"B\r
\n" ); document.write( "\n" ); document.write( " we can express this relationship as p= kB\r
\n" ); document.write( "\n" ); document.write( "where k is the constant .\r
\n" ); document.write( "\n" ); document.write( "The monthly payment is $8.99 for every $1000 borrowed.\r
\n" ); document.write( "\n" ); document.write( " Therefore, we get p =8.99*(B/1000)\r
\n" ); document.write( "\n" ); document.write( "Simplify
\n" ); document.write( "p= 0.00899 B \r
\n" ); document.write( "\n" ); document.write( " the amount borrowed B is $175,000\r
\n" ); document.write( "\n" ); document.write( "we can substitute 𝐵=175000 into the equation:\r
\n" ); document.write( "\n" ); document.write( "p = 0.00899 * 175000
\n" ); document.write( "p= 1573.25\r
\n" ); document.write( "\n" ); document.write( " The monthly payment p for the amount borrowed ($175,000) is $1753.25\r
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