document.write( "Question 1207782: 1. Suppose that you have entered an 87-mile biathlon that consists of a run and a bicycle race. During Explaining Concepts:Discussion and Writing your run, your average speed is 6 miles per hour, and during your bicycle race, your average speed is 25 miles per hour. You finish the race in 5 hours. What is the distance of the run? What is the distance of the bicycle race? \r
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\n" ); document.write( "\n" ); document.write( "2. In the 1984 Olympics, C.Lewis of the United States won the gold medal in the 100-meter race with a time of 9.99 seconds. In the 1896 Olympics,Thomas Burke,also of the United States, won the gold medal in the 100-meter race in 12.0 seconds. If they ran in the same race repeating their respective times, by how many meters would Lewis beat Burke? \r
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Algebra.Com's Answer #846093 by MathTherapy(10552) $\"\"$ $\"About$

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document.write( "1. Suppose that you have entered an 87-mile biathlon that consists of a run and a bicycle race. During Explaining Concepts:Discussion and Writing your run, your average speed is 6 miles per hour, and during your bicycle race, your average speed is 25 miles per hour. You finish the race in 5 hours. What is the distance of the run? What is the distance of the bicycle race? \r\n" );
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document.write( "2. In the 1984 Olympics, C.Lewis of the United States won the gold medal in the 100-meter race with a time of 9.99 seconds. In the 1896 Olympics,Thomas Burke,also of the United States, won the gold medal in the 100-meter race in 12.0 seconds. If they ran in the same race repeating their respective times, by how many meters would Lewis beat Burke? \r\n" );
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document.write( "I'll do no. 1, ONLY!\r\n" );
document.write( "Let distance of run, be D\r\n" );
document.write( "Then, distance of bicycle race = 87 - D (Total distance of the biathlon is 87 miles)\r\n" );
document.write( "As , it follows that the:  \r\n" );
document.write( "                                              \r\n" );
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document.write( "This gives us the following TIME equation:\r\n" );
document.write( "  \r\n" );
document.write( "      ----- Substituting D for RUN-DISTANCE, 6 for RUN-SPEED, \"87 - D\" for\r\n" );
document.write( "                           RACE-DISTANCE, 25 for RACE-SPEED, and 5 for BIATHLON-TIME\r\n" );
document.write( "25D + 6(87 - D) = 5(150) ----- Multiplying by LCD, 150\r\n" );
document.write( " 25D + 522 - 6D = 750\r\n" );
document.write( "       25D - 6D = 750 - 522\r\n" );
document.write( "            19D = 228\r\n" );
document.write( "RUN-DISTANCE, or \r\n" );
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document.write( "RACE-DISTANCE = 87 - D = 87 - 12 = 75 miles

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