document.write( "Question 1207922: Let U = {q, r, s, t, u, v, w, x, y, z} A = {q, s, u, w, y} B = {q, s, y, z} C = {v, w, x, y, z}.
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Algebra.Com's Answer #846054 by Edwin McCravy(20056)\"\" \"About 
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document.write( "A ∩ (B ∪ C)c\r\n" );
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document.write( "Substitute the sets for the capital letters:\r\n" );
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document.write( "{q, s, u, w, y} ∩ ({q, s, y, z} ∪ {v, w, x, y, z})c\r\n" );
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document.write( "Do in the parentheses first which is a \"∪\", which means \"union\", so we \r\n" );
document.write( "combine the two sets on each side of the \"∪\" into one (we don't repeat \r\n" );
document.write( "the y or z, which are elements of both):\r\n" );
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document.write( "{q, s, u, w, y} ∩ ({q, s, y, z, v, w, x})c\r\n" );
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document.write( "Now we do the \"c\", which means \"complement\", by replacing it with \r\n" );
document.write( "all the elements of U, the universal set, that are not in \r\n" );
document.write( "{q, s, y, z, v, w, x}\r\n" );
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document.write( "So when we remove all those from U, the universal set, we have this left\r\n" );
document.write( "{r, t, u} so that's the complement set.  So now we have\r\n" );
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document.write( "{q, s, u, w, y} ∩ {r, t, u}\r\n" );
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document.write( "Now we do the \"∩\", which means \"intersection\", so we take only the \r\n" );
document.write( "elements that are common to both sets, and ignore all the others. So the final\r\n" );
document.write( "answer is {u}, which has only one element, and is called a \"singleton\".\r\n" );
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document.write( "Answer: {u}\r\n" );
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document.write( "Edwin
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