document.write( "Question 1207918: For A and B, find the standard form of the equation of each circle.\r
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document.write( "A. Center (1,0) and has the point (-3,2).\r
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document.write( "B. Center (-3,1) and tangent to the y-axis. \n" );
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Algebra.Com's Answer #846048 by mananth(16946)![]() ![]() You can put this solution on YOUR website! A\r \n" ); document.write( "\n" ); document.write( "iven: \n" ); document.write( "• Center: (1,0)\r \n" ); document.write( "\n" ); document.write( "• Point on the circle: (−3,2) \n" ); document.write( "We find the radius r by the distance between the center and the given point by the distance formula: \n" ); document.write( "r=sqrt((x2−x1)^2+(y2−y1)^2)\r \n" ); document.write( "\n" ); document.write( "Substitute the given coordinates \r \n" ); document.write( "\n" ); document.write( "r=sqrt((−3)−1)^2+(2−0)^2) \n" ); document.write( "r = sqrt(20) \n" ); document.write( "r= 2 sqrt(5)\r \n" ); document.write( "\n" ); document.write( "Equation of circle \n" ); document.write( "(x-1)^2+ (y-0)^2 = (2sqrt(5))^2\r \n" ); document.write( "\n" ); document.write( "(x-1)^2+y^2= 20 ---------------------------A\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Given: center (−3,1) \n" ); document.write( "Tangent to the y-axis \n" ); document.write( "Since the circle is tangent to the y-axis, the radius r is the horizontal distance from the center to the y-axis. The x-coordinate of the center is −3 \r \n" ); document.write( "\n" ); document.write( "so the radius 𝑟 =3\r \n" ); document.write( "\n" ); document.write( "(x−(−3)) ^2 +(y−1) ^2 = 3^2=9\r \n" ); document.write( "\n" ); document.write( "(x+3)^2 +(y-1)^2 = 9 \n" ); document.write( " \n" ); document.write( " |