document.write( "Question 116333This question is from textbook
\n" ); document.write( ": 3 over 2 x - 5 over 3y + 1 over 6 z =0 for y when x=4 and z =3 \n" ); document.write( "

Algebra.Com's Answer #84604 by ilana(307) $\"\"$ $\"About$

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I believe the equation you have is (3/2x)-(5/3y)+(1/6z)=0.
\n" ); document.write( "Now you have x=4 and z=3, which changes the equation to (3/2(4))-(5/3y)+(1/6(3))=0, or (3/8)-(5/3y)+(1/18)=0. Separating terms with y from constant terms gives (3/8)+(1/18)=5/3y.
\n" ); document.write( "72 is a common denominator on the left, so we could multiply 3/8 by 9/9 and multiply 1/18 by 4/4 to get (27/72)+(4/72)=5/3y. Combining gives 31/72=5/3y.
\n" ); document.write( "Cross multiplying gives 31*3y=5*72, so 93y=360, so y=360/93=120/31. \n" ); document.write( "

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