document.write( "Question 1207888: 1. To estimate with 95% confidence the average number of kilometres that students living off-campus commute to classes every day, a random sample of 20 students was taken and produced a mean equal to 5.2 km and a standard deviation of 3.05 km. Under these circumstances, what is the appropriate critical value?
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document.write( "a. 2.093
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document.write( "b. 1.960
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document.write( "c. 2.086
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document.write( "d. 1.729 \n" );
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Algebra.Com's Answer #846017 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "n = 20 = sample size \n" ); document.write( "xbar = 5.2 = sample mean \n" ); document.write( "s = 3.05 = sample standard deviation \n" ); document.write( "sigma = population standard deviation = unknown\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We don't know the value of sigma and n > 30 is not the case, so we must use the T distribution. \n" ); document.write( "df = degrees of freedom \n" ); document.write( "df = n-1 \n" ); document.write( "df = 20-1 \n" ); document.write( "df = 19\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "You could use a stats calculator like a TI83 to find the T critical value. \n" ); document.write( "However, I'll use a T table such as this \n" ); document.write( "https://www.sjsu.edu/faculty/gerstman/StatPrimer/t-table.pdf \n" ); document.write( "Such a table can be found at the back of your stats textbook. \n" ); document.write( "Highlight the df = 19 row and the column that mentions \"confidence level = 95%\" (mentioned at the bottom of the table) \n" ); document.write( "The intersection of this row and column yields the approximate t critical value t = 2.093\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "What does this tell us? \n" ); document.write( "It tells us that P(-2.093 < t < 2.093) = 0.95 approximately when df = 19. \n" ); document.write( "The 0.95 is the area of the main body while 1-0.95 = 0.05 is the combined area of the two tails. \n" ); document.write( "The 0.95 refers to the confidence level 95%.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The final answer is option A \n" ); document.write( " \n" ); document.write( " |