document.write( "Question 1207746: Two cars enter the Florida Turnpike at Commercial Boulevard at 8:00 AM, each heading for Wildwood.One car’s average speed is 10 miles per hour more than the other’s.The faster car arrives at Wildwood at 11:00 AM, (1/2) hour before the other car.What was the average speed of each car? How far did each travel? \n" ); document.write( "
Algebra.Com's Answer #845994 by josgarithmetic(39625) ![]() You can put this solution on YOUR website! \r\n" ); document.write( " SPEED TIME DISTANCE\r\n" ); document.write( "\r\n" ); document.write( "SLOWER r d/r d\r\n" ); document.write( "\r\n" ); document.write( "FASTER r+10 d/(r+10) d\r\n" ); document.write( "\r\n" ); document.write( "DIFFERENCE 1/2\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Just seem easier to pick the unknown distance that each travels until each \n" ); document.write( "arrives to be the variable.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This analysis is better: \n" ); document.write( "Both start at reference spot 8 a.m. \n" ); document.write( "Faster car completes distance in 3 hours (at 11 a.m.) \n" ); document.write( "so slower car needed 3.5 hours (the half hour difference) \n" ); document.write( " \r\n" ); document.write( " SPEED TIME DISTANCE\r\n" ); document.write( "\r\n" ); document.write( "SLOWER r 3.5 d\r\n" ); document.write( "\r\n" ); document.write( "FASTER r+10 3.0 d\r\n" ); document.write( "\r\n" ); document.write( "DIFFERENCE 1/2\r\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |