document.write( "Question 1207746: Two cars enter the Florida Turnpike at Commercial Boulevard at 8:00 AM, each heading for Wildwood.One car’s average speed is 10 miles per hour more than the other’s.The faster car arrives at Wildwood at 11:00 AM, (1/2) hour before the other car.What was the average speed of each car? How far did each travel? \n" ); document.write( "
Algebra.Com's Answer #845992 by greenestamps(13206) You can put this solution on YOUR website! \n" ); document.write( "Here is another non-algebraic way to solve the problem quickly and easily. \n" ); document.write( "The faster car finished the trip in 3 hours; the slower car finished in 3.5 hours. \n" ); document.write( "Since the distances are the same and the ratio of times is 3/3.5=6/7, the ratio of speeds is 7/6. \n" ); document.write( "Since the ratio of speed is 7/6 and the difference in speeds is 10mph, the two speeds are 70mph and 60mph. \n" ); document.write( "(You can reach that conclusion by observation and simple logical reasoning, or you can do it more formally using a proportion.) \n" ); document.write( "ANSWERS: \n" ); document.write( "speed of faster car: 70mph \n" ); document.write( "speed of slower car: 60mph \n" ); document.write( "distance each car traveled: 70(3)=210 miles, or 60(3.5)=210 miles \n" ); document.write( " \n" ); document.write( " |