document.write( "Question 1207821: An artist has 50 inches of oak trim to frame a painting. The frame is to have a border 3 inches wide surrounding the painting. \r
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document.write( "(a) If the painting is square, what are its dimensions? What are the dimensions of the frame? \r
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document.write( "(b) If the painting is rectangular with a length twice its width, what are the dimensions of the painting? What are the dimensions of the frame? \n" );
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Algebra.Com's Answer #845945 by mananth(16946) You can put this solution on YOUR website! An artist has 50 inches of oak trim to frame a painting. The frame is to have a border 3 inches wide surrounding the painting. \r \n" ); document.write( "\n" ); document.write( "(a) If the painting is square, what are its dimensions? What are the dimensions of the frame? \r \n" ); document.write( "\n" ); document.write( "(b) If the painting is rectangular with a length twice its width, what are the dimensions of the painting? What are the dimensions of the frame?\r \n" ); document.write( "\n" ); document.write( "An artist has 50 inches of oak trim to frame a painting. The frame is to have a border 3 inches wide surrounding the painting. \r \n" ); document.write( "\n" ); document.write( "Let the side of the painting be x inches \n" ); document.write( "There is a border of 3 inches all round.\r \n" ); document.write( "\n" ); document.write( "length of the side of frame will be (x+6) ( 3 in on either side.)\r \n" ); document.write( "\n" ); document.write( "Perimeter is 50 inches\r \n" ); document.write( "\n" ); document.write( "4(x+6) =50 ( 4 sides)\r \n" ); document.write( "\n" ); document.write( "4x+24 =50 \n" ); document.write( "4x= 26 \n" ); document.write( "x= 6.5 inches \n" ); document.write( "Painting is a square with side 6.5 inches and frame with 12.5 inches side\r \n" ); document.write( "\n" ); document.write( "(b) If the painting is rectangular with a length twice its width, what are the dimensions of the painting? What are the dimensions of the frame?\r \n" ); document.write( "\n" ); document.write( "Let width of painting be x in. the length will be 2x \n" ); document.write( "frame dimensions \n" ); document.write( "x+6 and 2x+6\r \n" ); document.write( "\n" ); document.write( "perimeter \r \n" ); document.write( "\n" ); document.write( "2(x+6)+2(2x+6)=50 \r \n" ); document.write( "\n" ); document.write( "2x+12 +4x+12=50 \n" ); document.write( "6x = 26 \n" ); document.write( "x= 4.33 with \n" ); document.write( "Length = 2x= 8.66 in \n" ); document.write( "Add 6 to both sides to get the frame dimensions\r \n" ); document.write( "\n" ); document.write( " The dimensions of the framed painting are 10.33 inches by 14.67 inches.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |