document.write( "Question 1207821: An artist has 50 inches of oak trim to frame a painting. The frame is to have a border 3 inches wide surrounding the painting. \r
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document.write( "(a) If the painting is square, what are its dimensions? What are the dimensions of the frame? \r
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document.write( "(b) If the painting is rectangular with a length twice its width, what are the dimensions of the painting? What are the dimensions of the frame? \n" );
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Algebra.Com's Answer #845939 by greenestamps(13209) You can put this solution on YOUR website! \n" ); document.write( "Technically, the statement of the problem is deficient, because it does not say that the artist uses the full 50 inches of trim. \n" ); document.write( "Obviously the problem can be solved only if we assume that he does. So.... \n" ); document.write( "(a) If the painting is a square... \n" ); document.write( "Let x be the side length of the painting; then the perimeter is 4x, and the perimeter of the painting plus frame is 4(x+3) = 4x+12. \n" ); document.write( "4x+12 = 50 \n" ); document.write( "4x = 38 \n" ); document.write( "x = 38/4 = 19/2 = 9.5 \n" ); document.write( "ANSWERS: \n" ); document.write( "The painting is a square 9.5 inches on a side. \n" ); document.write( "The frame is a square 9.5+2(3) = 15.5 inches on a side. \n" ); document.write( "(b) If the painting is a rectangle with a length twice its width... \n" ); document.write( "Let x be the width; then the length is 2x; the perimeter is 6x, and the perimeter of the frame is 6x+12. \n" ); document.write( "6x+12 = 50 \n" ); document.write( "6x = 38 \n" ); document.write( "x = 38/6 = 19/3 = 6 1/3 \n" ); document.write( "ANSWERS: \n" ); document.write( "The painting is a rectangle 6 1/3 inches wide and 12 2/3 inches long. \n" ); document.write( "The frame is a rectangle 6 1/3 + 2(3) = 12 1/3 inches wide and 12 2/3 + 2(3) = 18 2/3 inches long. \n" ); document.write( " \n" ); document.write( " |