document.write( "Question 116278: x+1 < 2x +1 \n" ); document.write( "
Algebra.Com's Answer #84586 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"x%2B1%3C2x%2B1\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"x%3C2x%2B1-1\"Subtract 1 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x-2x%3C1-1\" Subtract 2x from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-x%3C1-1\" Combine like terms on the left side\r
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\n" ); document.write( "\n" ); document.write( "\"-x%3C0\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x%3E%280%29%2F%28-1%29\" Divide both sides by -1 to isolate x (note: Remember, dividing both sides by a negative number flips the inequality sign) \r
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\n" ); document.write( "\n" ); document.write( "\"x%3E0\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"x%3E0\" \r
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