document.write( "Question 1207779: Let z and w be complex numbers such that |z| = |w| = 1 and zw is not equal to -1.\r
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Algebra.Com's Answer #845858 by ikleyn(52787)\"\" \"About 
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\n" ); document.write( "Let z and w be complex numbers such that |z| = |w| = 1 and zw is not equal to -1.
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\n" ); document.write( "\n" ); document.write( "            Proof for part  (a)\r
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document.write( "It is well known fact that the product  \"z\".\"z%5Bconjugate%5D\" = |z|^2.\r\n" );
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document.write( "Indeed,  if z = a + bi, then  \"z%5Bconjugate%5D\" = a - bi,  and, therefore,\r\n" );
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document.write( "    \"z\".\"z%5Bconjugate%5D\" = (a+bi)*(a-bi) = \"a%5E2-i%5E2%2Ab%5E2\" = \"a%5E2-1%2Ab%5E2\" = \"a%5E2%2Bb%5E2\" = \"abs%28z%29%5E2\".\r\n" );
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document.write( "But we are given that  |z| = 1;  hence,  \"abs%28z%29%5E2\" = 1.\r\n" );
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document.write( "Thus \"z\".\"z%5Bconjugate%5D\" = 1.\r\n" );
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document.write( "Hence,  \"z%5Bconjugate%5D\" = \"1%2Fz\".\r\n" );
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document.write( "It is what was required to prove.\r\n" );
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document.write( "For  \"w%5Bconjugate%5D\" = \"1%2Fw\"  the proof is the same.\r\n" );
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document.write( "It is, actually, the same statement as  \"z%5Bconjugate%5D\" = \"1%2Fz\",  but expressed using letter w instead of z.\r\n" );
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\n" ); document.write( "\n" ); document.write( "At this point,  proof for part  (a)  is complete.\r
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\n" ); document.write( "\n" ); document.write( "            Proof for part  (b)\r
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document.write( "z and w are unit complex numbers, in the sense that their modules are equal to 1 (given).\r\n" );
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document.write( "Hence, in geometric presentation in complex plane, z and w are adjacent side of a rhombus.\r\n" );
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document.write( "Then, according to the parallelogram rule of adding complex numbers, the sum z+w\r\n" );
document.write( "is the diagonal of the rhombus on side z and w.\r\n" );
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document.write( "According to properties of a rhombus, its diagonal is a bisector of the angle \r\n" );
document.write( "between vectors z and w.\r\n" );
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document.write( "Therefore, for the argument of the complex number  z+w  we can write\r\n" );
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document.write( "    arg(z+w) = \"%281%2F2%29%2A%28arg%28z%29%2Barg%28w%29%29\"  mod \"2pi\".    (1)\r\n" );
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document.write( "Now consider complex number zw.  As the product of two complex unit numbers, it is a unit\r\n" );
document.write( "complex number, too, i.e. has the modulus 1, and its argument is the sum of arguments z and w\r\n" );
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document.write( "    arg(zw) = arg(z) + arg(w)  mod  \"2pi\".    (2)\r\n" );
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document.write( "Also, notice that  \"1\"  is a complex unit number too, with the argument arg(1) = 0.\r\n" );
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document.write( "Applying the same proof as in (1),  we get\r\n" );
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document.write( "     arg(zw+1) = \"%281%2F2%29%2A%28arg%28zw%29+%2B+arg%281%29%29\" = \"%281%2F2%29%2A%28arg%28zw%29+%2B+0%29\" = \"%281%2F2%29%2Aarg%28zw%29\"  mod \"2pi\".    (3)\r\n" );
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document.write( "Using (2), we can continue line (3) this way\r\n" );
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document.write( "     arg(zw+1) = \"%281%2F2%29%2A%28arg%28z%29+%2B+arg%28w%29%29\"  mod \"2pi\".   (4)\r\n" );
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document.write( "Comparing (1) with (4), we see that\r\n" );
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document.write( "    arg(z+w) = arg(zw+1)  mod \"pi\".\r\n" );
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document.write( "It means that complex numbers  z+w  and  (zw+1)  are either co-directed vectors or oppositely directed vectors.\r\n" );
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document.write( "In any case, it implies that the number  \"%28z%2Bw%29%2F%28zw%2B1%29\"  has the argument 0 or \"pi\"  mod \"2pi\",\r\n" );
document.write( "i.e. is a real number.\r\n" );
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document.write( "At this point, the proof  (b)  is complete.\r\n" );
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