document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1207751>Question 1207751</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Patrick, by himself, can paint four rooms in 10 hours. If he hires April to help, they can do the same job together in 6 hours. If he lets April work alone, how long will it take her to paint four rooms?\r<BR>\n" );
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document.write( "Let me see.\r<BR>\n" );
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document.write( "Patrick = 1/10\r<BR>\n" );
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document.write( "April = 1/x\r<BR>\n" );
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document.write( "Together = 1/6\r<BR>\n" );
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document.write( "(1/10) + (1/x) = (1/6)\r<BR>\n" );
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document.write( "Is this the correct equation?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #845844 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13196)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=845844\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is another way to solve this kind of problem without using fractions.<br><BR>\n" );
document.write( "Consider the least common multiple of the two given times, which is 30 hours.<br><BR>\n" );
document.write( "In 30 hours, Patrick himself could paint the four rooms 30/10 = 3 times; in 30 hours, the two together could paint the four rooms 30/6 = 5 times.<br><BR>\n" );
document.write( "That means in 30 hours April alone could paint the four rooms 5-3 = 2 times.<br><BR>\n" );
document.write( "And that means she could paint the four rooms alone in 30/2 = 15 hours.<br><BR>\n" );
document.write( "ANSWER: 15 hours.<br><BR>\n" );
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