document.write( "Question 1207767: A 5-horsepower (hp) pump can empty a pool in 5 hours.A smaller, 2-hp pump empties the same pool in 8 hours. The pumps are used together to begin emptying this pool.After two hours, the 2-hp pump breaks down. How long will it take the larger pump to empty the pool? \n" ); document.write( "
Algebra.Com's Answer #845826 by mananth(16946)\"\" \"About 
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\n" ); document.write( "A 5-horsepower (hp) pump can empty a pool in 5 hours.A smaller, 2-hp pump empties the same pool in 8 hours. The pumps are used together to begin emptying this pool.After two hours, the 2-hp pump breaks down. How long will it take the larger pump to empty the pool?\r
\n" ); document.write( "\n" ); document.write( "Consider emptying the pool is 1 job\r
\n" ); document.write( "\n" ); document.write( "A 5-horsepower (hp) pump can empty a pool in 5 hours. rate of Emptying = 1/5 of the job\r
\n" ); document.write( "\n" ); document.write( "A smaller, 2-hp pump empties the same pool in 8 hours.1/8 of the job\r
\n" ); document.write( "\n" ); document.write( " The pumps are used together for two hours \r
\n" ); document.write( "\n" ); document.write( "2(1/5 +1/8) of the job is done in two hours =26/40 = 13/20\r
\n" ); document.write( "\n" ); document.write( "Balance job = 1- 13/20 = 7/20 \r
\n" ); document.write( "\n" ); document.write( "1/5 of job the 5Hp does in 1 hour
\n" ); document.write( "7/20 of the job it will do in (7/20)/ (1/5)= 35/20 = 7/4 hours\r
\n" ); document.write( "\n" ); document.write( " It will take the 5-hp pump an additional 1.75 hours to empty the pool after the 2-hp pump breaks down.\r
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