document.write( "Question 1207770: Mike can run the mile in 6 minutes, and Dan can run the mile in 9 minutes. If Mike gives Dan a head start of 1 minute, how far from the start will Mike pass Dan? How long does it take? \n" ); document.write( "
Algebra.Com's Answer #845823 by mananth(16946)\"\" \"About 
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Mike can run the mile in 6 minutes, and Dan can run the mile in 9 minutes. If Mike gives Dan a head start of 1 minute, how far from the start will Mike pass Dan? How long does it take?\r
\n" ); document.write( "\n" ); document.write( "Mike can run the mile in 6 minutes, speed = 1/6 mi /minute
\n" ); document.write( " and Dan can run the mile in 9 minutes. = 1/9 mi /minute\r
\n" ); document.write( "\n" ); document.write( "Mike gives Dan a head start of 1 minute
\n" ); document.write( "It means the Dan is nine miles ahead of mike when Mike starts to run\r
\n" ); document.write( "\n" ); document.write( "So Mile has to catchup 9 miles . catchup distance = 1/9 miles
\n" ); document.write( "Catch up speed = 1/6-1/9= 1/18 miles / minute\r
\n" ); document.write( "\n" ); document.write( "d/r = t\r
\n" ); document.write( "\n" ); document.write( "catchup time = catchup distance / catchup speed\r
\n" ); document.write( "\n" ); document.write( "(1/9)/(1/18)= 2 minutes\r
\n" ); document.write( "\n" ); document.write( "Distance covered by Mike in 2 minutes: 1/6×2=2/6=1/3\r
\n" ); document.write( "\n" ); document.write( "Mike will pass Dan 1/3 miles from the start, and it will take him 2 minutes to do so.\r
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