document.write( "Question 1207762: An air rescue plane averages 300 miles per hour in still air. It carries enough fuel for 5 hours of flying time. If, upon takeoff, it encounters a head wind of 30 mi/hr, how far can it fly and return safely? (Assume that the wind remains constant.) \n" ); document.write( "
Algebra.Com's Answer #845809 by mananth(16946)\"\" \"About 
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An air rescue plane averages 300 miles per hour in still air. It carries enough fuel for 5 hours of flying time. If, upon takeoff, it encounters a head wind of 30 mi/hr, how far can it fly and return safely? (Assume that the wind remains constant.)\r
\n" ); document.write( "\n" ); document.write( "Speed of plane in still air 300 mph
\n" ); document.write( "Head wind = 30 mph\r
\n" ); document.write( "\n" ); document.write( "Fuel available for 5 hours
\n" ); document.write( "It means the plane can fly a total distance of 5*300= 1500 miles (to & fro)
\n" ); document.write( "Tail wind when returning 30 mph\r
\n" ); document.write( "\n" ); document.write( "x/(300-30) + x/(300+30)= 5\r
\n" ); document.write( "\n" ); document.write( "x/270+x/330 =5\r
\n" ); document.write( "\n" ); document.write( "11x/(11*270 )+ 9x/(9*330)=5\r
\n" ); document.write( "\n" ); document.write( "(11x +9x)/2970 =5\r
\n" ); document.write( "\n" ); document.write( "20x = 14850\r
\n" ); document.write( "\n" ); document.write( "x = 742.50 \r
\n" ); document.write( "\n" ); document.write( "The plane can fly 742.5 miles one way and then return safely, in the given conditions\r
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