document.write( "Question 1207748: Construct the indicated confidence interval for the population mean mu using theβ t-distribution. Assume the population is normally distributed.
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document.write( "cequals0.98β, x overbarequals13.6β, sequals0.94β, nequals19 \n" );
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Algebra.Com's Answer #845793 by math_tutor2020(3817) ![]() You can put this solution on YOUR website! \n" ); document.write( "xbar = sample mean \n" ); document.write( "s = sample standard deviation \n" ); document.write( "n = sample size \n" ); document.write( "df = degrees of freedom\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "xbar = 13.6 \n" ); document.write( "s = 0.94 \n" ); document.write( "n = 19 \n" ); document.write( "df = n-1 = 19-1 = 18 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use a T table such as this one \n" ); document.write( "https://www.sjsu.edu/faculty/gerstman/StatPrimer/t-table.pdf \n" ); document.write( "Similar tables should be found in the back of your stats textbook. \n" ); document.write( "Use that table to determine the t critical value is roughly t = 2.552 at a 98% confidence level and when df = 18. \n" ); document.write( "The confidence levels are labeled at the bottom. \n" ); document.write( "What this indicates is that P(-2.552 < T < 2.552) = 0.98 approximately when df = 18.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's compute the margin of error. \n" ); document.write( "E = t*s/sqrt(n) \n" ); document.write( "E = 2.552*0.94/sqrt(19) \n" ); document.write( "E = 0.55034082 approximately\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use this to find the lower and upper bounds (L and U) \n" ); document.write( "L = xbar - E \n" ); document.write( "L = 13.6 - 0.55034082 \n" ); document.write( "L = 13.04965918 \n" ); document.write( "L = 13.05\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "U = xbar + E \n" ); document.write( "U = 13.6 + 0.55034082 \n" ); document.write( "U = 14.15034082 \n" ); document.write( "U = 14.15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Depending how you round the final answer, the 98% confidence interval for the population mean is approximately (13.05, 14.15) \n" ); document.write( "This is in the format (L, U)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Another way to express the confidence interval would be to say 13.05 < mu < 14.15 \n" ); document.write( "This is of the format L < mu < U which I think is more descriptive since we're involving the parameter being estimated (mu). \n" ); document.write( " \n" ); document.write( " |