document.write( "Question 1207748: Construct the indicated confidence interval for the population mean mu using the​ t-distribution. Assume the population is normally distributed.
\n" ); document.write( "cequals0.98​, x overbarequals13.6​, sequals0.94​, nequals19
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Algebra.Com's Answer #845793 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "xbar = sample mean
\n" ); document.write( "s = sample standard deviation
\n" ); document.write( "n = sample size
\n" ); document.write( "df = degrees of freedom\r
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\n" ); document.write( "\n" ); document.write( "xbar = 13.6
\n" ); document.write( "s = 0.94
\n" ); document.write( "n = 19
\n" ); document.write( "df = n-1 = 19-1 = 18 \r
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\n" ); document.write( "\n" ); document.write( "Use a T table such as this one
\n" ); document.write( "https://www.sjsu.edu/faculty/gerstman/StatPrimer/t-table.pdf
\n" ); document.write( "Similar tables should be found in the back of your stats textbook.
\n" ); document.write( "Use that table to determine the t critical value is roughly t = 2.552 at a 98% confidence level and when df = 18.
\n" ); document.write( "The confidence levels are labeled at the bottom.
\n" ); document.write( "What this indicates is that P(-2.552 < T < 2.552) = 0.98 approximately when df = 18.\r
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\n" ); document.write( "\n" ); document.write( "Let's compute the margin of error.
\n" ); document.write( "E = t*s/sqrt(n)
\n" ); document.write( "E = 2.552*0.94/sqrt(19)
\n" ); document.write( "E = 0.55034082 approximately\r
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\n" ); document.write( "\n" ); document.write( "Use this to find the lower and upper bounds (L and U)
\n" ); document.write( "L = xbar - E
\n" ); document.write( "L = 13.6 - 0.55034082
\n" ); document.write( "L = 13.04965918
\n" ); document.write( "L = 13.05\r
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\n" ); document.write( "\n" ); document.write( "U = xbar + E
\n" ); document.write( "U = 13.6 + 0.55034082
\n" ); document.write( "U = 14.15034082
\n" ); document.write( "U = 14.15\r
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\n" ); document.write( "\n" ); document.write( "Depending how you round the final answer, the 98% confidence interval for the population mean is approximately (13.05, 14.15)
\n" ); document.write( "This is in the format (L, U)\r
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\n" ); document.write( "\n" ); document.write( "Another way to express the confidence interval would be to say 13.05 < mu < 14.15
\n" ); document.write( "This is of the format L < mu < U which I think is more descriptive since we're involving the parameter being estimated (mu).
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