document.write( "Question 1207745: A candy store sells boxes of candy containing caramels and cremes.Each box sells for $12.50 and holds 30 pieces of candy (all pieces are the same size).If the caramels cost $0.25 to produce and the cremes cost $0.45 to produce,how many of each should be in a box to make a profit of $3? \n" ); document.write( "
Algebra.Com's Answer #845791 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Here is a solution by an informal method that can be used to solve any 2-part \"mixture\" problem like this (if formal algebra is not required). \n" ); document.write( "To make a profit of $3 on each box if the selling price is $12.50, the cost of production needs to be $12.50-$3 = $9.50. \n" ); document.write( "The cost of producing 30 caramels would be 30($0.25) = $7.50; the cost of producing 30 cremes would be 30($0.45) = $13.50. \n" ); document.write( "Use mental arithmetic to see that $9.50 is 1/3 of the way from $7.50 to $13.50. \n" ); document.write( "That means 1/3 of the candies should be the more expensive cremes. \n" ); document.write( "1/3 of 30 is 10. \n" ); document.write( "ANSWER: 10 cremes and 20 caramels \n" ); document.write( " \n" ); document.write( " |