document.write( "Question 1207746: Two cars enter the Florida Turnpike at Commercial Boulevard at 8:00 AM, each heading for Wildwood.One car’s average speed is 10 miles per hour more than the other’s.The faster car arrives at Wildwood at 11:00 AM, (1/2) hour before the other car.What was the average speed of each car? How far did each travel? \n" ); document.write( "
Algebra.Com's Answer #845786 by mccravyedwin(408)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "One car’s average speed is 10 miles per hour more than the other’s.\r\n" );
document.write( "\r\n" );
document.write( "So, during each of the 3 hours between 8AM and 11AM, The faster car gained an\r\n" );
document.write( "additional 10 miles lead over the slower car. \r\n" );
document.write( "\r\n" );
document.write( "So when the faster car arrived at his destination (in Wildwood), the slower car\r\n" );
document.write( "was still (10)(3) = 30 miles behind. \r\n" );
document.write( "\r\n" );
document.write( "It then took the slower car 1/2 hour to go those 30 miles.  \r\n" );
document.write( "\r\n" );
document.write( "Since the slower car went 30 miles in 1/2 hour, it could have gone 60 miles in 1\r\n" );
document.write( "whole hour, so the slower car averaged 60 mph.\r\n" );
document.write( "\r\n" );
document.write( "Therefore, the faster car averaged 60+10=70 mph.\r\n" );
document.write( "\r\n" );
document.write( "So in 3 hours the faster car went (70)(3) = 210 miles.\r\n" );
document.write( "\r\n" );
document.write( "Answers:\r\n" );
document.write( "\r\n" );
document.write( "The slower car averaged 60 mph.\r\n" );
document.write( "The faster car averaged 70 mph.\r\n" );
document.write( "Each traveled 210 miles.\r\n" );
document.write( "\r\n" );
document.write( "Now I'll let the other tutors put some algebra in the solution.  For mine's too\r\n" );
document.write( "\"arithmeticky\". \r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );