document.write( "Question 1207733: Solve the absolute value equation. \r
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document.write( "Solve |x + |3x-2|| = 2\r
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document.write( "Note: Here we have an absolute value inside another absolute value. \n" );
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Algebra.Com's Answer #845779 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "If we think of this as a function, we know the behavior of the graph changes when (3x-2) is 0 -- i.e., at x=2/3. So let's solve two separate absolute value equations, considering only values of x greater than or equal to 2/3 in one equation and considering only values of x less than 2/3 in the other. \n" ); document.write( "(1) If x is greater than or equal to 2/3, then |3x-2| is equal to 3x-2: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(1a) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x=1 satisfies our condition that x is greater than or equal to 2/3, so x=1 is a solution. \n" ); document.write( "OR \n" ); document.write( "(1b) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x=0 does NOT satisfy our condition that x is greater than or equal to 2/3, so x=0 is not a solution. \n" ); document.write( "(2) If x is less than 2/3, then |3x-2| is equal to -(3x-2) = -3x+2: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(2a) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x=0 satisfies our condition that x is less than 2/3, so x=0 is a solution. \n" ); document.write( "OR \n" ); document.write( "(2b) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x=2 does NOT satisfy our condition that x is less than 2/3, so x=2 is not a solution. \n" ); document.write( "We found two solutions above, in cases (1a) and (2a). \n" ); document.write( "ANSWER: x=1 or x=0 \n" ); document.write( " \n" ); document.write( " |