document.write( "Question 1207722: Solve the inequality. Express your answer using set notation or interval notation. Graph the solution set. \r
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Algebra.Com's Answer #845752 by ikleyn(52847) $\"\"$ $\"About$

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\n" ); document.write( "Solve the inequality. Express your answer using set notation or interval notation. Graph the solution set.\r
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document.write( "Your starting inequality is\r\n" );
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document.write( "    0 <  < .    (1)\r\n" );
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document.write( "Left part of this inequality,  0 < ,  means that the denominator is positive\r\n" );
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document.write( "    3x + 6 > 0    (otherwise,    would be negative).\r\n" );
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document.write( "It implies  3x > - 6,  x >  = -2.    (2)\r\n" );
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document.write( "Right part of this inequality is\r\n" );
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document.write( "     < .\r\n" );
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document.write( "Assuming that 3x+6 is positive, we can multiply both sides by 3x+6 without flipping the inequality sign.\r\n" );
document.write( "By doing it, we get\r\n" );
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document.write( "    1 < ,\r\n" );
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document.write( "or, equivalently,\r\n" );
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document.write( "    1 < x+2.\r\n" );
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document.write( "It implies \r\n" );
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document.write( "    x > -1.    (3)\r\n" );
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document.write( "So, we have two inequalities,  (2) and (3).\r\n" );
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document.write( "Therefore, the final answer is  the intersection of these two sets,  x > -1.\r\n" );
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document.write( "In the interval form, the solution set is  (-1,infinity).\r\n" );
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document.write( "This is a graph\r\n" );
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document.write( "   ----|--------|--------(========|========|========|======>\r\n" );
document.write( "       -3       -2       -1       0        1        2     x\r\n" );
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