document.write( "Question 1207707: If 0 < a < b, show that a < sqrt{a•b} < b. The number sqrt{a•b} is called the geometric mean of a and b.\r
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Algebra.Com's Answer #845740 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "a < sqrt(ab) < b is the ultimate goal we want to reach.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Break it into these two key parts \n" ); document.write( "a < sqrt(ab) and sqrt(ab) < b\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's focus on the first part \n" ); document.write( "a < sqrt(ab) \n" ); document.write( "a^2 < ab ......... square both sides \n" ); document.write( "a < b ........... divide both sides by 'a'\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The inequality sign won't flip when dividing both sides by 'a' since a > 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's reverse the flow of that logic to get this: \n" ); document.write( "a < b \n" ); document.write( "a*a < b*a \n" ); document.write( "a^2 < ab \n" ); document.write( "sqrt( a^2 ) < sqrt(ab) \n" ); document.write( "a < sqrt(ab)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Follow a similar set of steps for the other key part. \n" ); document.write( "a < b \n" ); document.write( "a*b < b*b \n" ); document.write( "ab < b^2 \n" ); document.write( "sqrt(ab) < sqrt(b^2) \n" ); document.write( "sqrt(ab) < b\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We have determined \n" ); document.write( "a < sqrt(ab) and sqrt(ab) < b \n" ); document.write( "which glue together to get \n" ); document.write( "a < sqrt(ab) < b \n" ); document.write( " \n" ); document.write( " |